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VladimirAG [237]
2 years ago
8

Am I right?? I just need this one and another one!! need it asap! sorry if this is bothering you.​

Mathematics
1 answer:
Elden [556K]2 years ago
5 0

Answer:

No

Step-by-step explanation:

The correct answer is y = 3x, where y is the total cost and x is the number of pounds of oranges purchased.

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What is y= -2/3x + 5 written in standard form?
GaryK [48]

1) the standar form of the  equation is  ax+by  = c, therefore, for  y = -2/3x+5, multiply by 3 the previous equation, and its result is  3y = -2x+15⇒ 3y +2x = 15

the final result is  2x+3y = 15

 

6 0
4 years ago
Read 2 more answers
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

Therefore inflection points is given as

x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
3 years ago
Find the perimeter of the square in the coordinate plane below. Round your answer to two decimal places.​
tamaranim1 [39]
You have to show a picture so we can solve this problem you’re having.
7 0
4 years ago
Read 2 more answers
The answer to the problems and how to solve it.
swat32

Let x and y represent angles 1 and 2, respectively. The given relations tell you

... x + y = 180 . . . . the sum of measures of a linear pair is 180°

... y = 2x + 6 . . . . angle 2 is 6 more than twice angle 1

One way to solve these is to add twice the first equation to the second.

... 2(x + y) + (y) = 2(180) + (2x +6)

Now, subtract 2x

... 3y = 366

... y = 122 . . . . divide by the coefficient of y

The measure of angle 2 is 122°.

3 0
4 years ago
If F(x) = 9x, which of the following is the inverse of Fx)?
Arturiano [62]

Answer:

F⁻¹(x) = x/9

Step-by-step explanation:

To find the inverse of a function, you want to switch x and y in the equation and solve for y.

F(x) = 9x

x = 9F(x)

x/9 = F⁻¹(x)

Therefore, the inverse is F⁻¹(x) = x/9.

5 0
3 years ago
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