Answer:
OB. ll, lll, and lV
Explanation:
All of these are recessive, hunntingtons disease is dominent.
Answer:
the ewser is translation
Explanation:
it requires this process of nucleotide sequences into the amino acid sequences
Answer:
This exact same question is on my assignment and im in 6th grade..... so this should be easy for you.
Explanation:
But because im nice i will give you the answer. The answer is: In codominance, both alleles are expressed in the offspring while in incomplete dominance, the offspring demonstrates an intermediate form of the alleles from the parents.
Answer:
Codons. As we learned in Structure of Nucleic Acids, DNA and RNA are made up by sequences of nitrogen bases-pairs: adenine, thymine, guanine, and cytosine. Scientists have long understood that these nitrogen bases somehow contained the information that coded for specific amino acids.
Explanation:
Answer:
2/3
Explanation:
This question involves a single gene coding for the possession or not of Cystic Fibrosis (CF). Since, the disorder is inherited as a recessive pattern, it means the C allele (no CF) is dominant over c allele (CF). This means that only an individual with (cc) genotype can be affected.
However, if a cross between two unaffected parents produced a child with CF, it means both parents are heterozygous or carriers of the trait i.e. Cc genotype. Thus, using a punnet square, a cross between them will give rise to four possible offsprings with CC, Cc, Cc and cc genotypes.
Two children were given birth to, with one having the disorder (cc) and one not having. The CC, Cc, and Cc genotypes will not be affected but Cc will be a carrier. Therefore, the probability of having the unaffected children be a carrier is 2 out of the normal 3 children i.e. 2/3.
