X/4 - 12 = -18
x/4 -12 +12 = -18 + 12
x/4 = -6
x/4 times 4 = -6 times 4
x = -24
Check
-24 divided by 4 = -6 -12 = -18
You can use 1 of 2 methods to solve this problem. You can either solve it traditionally or by just looking at it (you don't necessarily need to convert it to scientific notation to find the answer).
{METHOD 1}- Traditional Method
Scientific Notation is just another way of writing REALLY BIG or REALLY SMALL numbers in a simplified manor
Let's take 232,000,000 for instance
First you want to find your decimal number. Your decimal number has to be Greater than 1 and less than 10.
In this case your decimal number will be 2.32
Then let's could how many decimal places are to the RIGHT of 2.32
Keep in mind that if the number is very small you have to count the decimal places to the LEFT
{METHOD 2}
If you look at 232,000,000 and 2,320,000,000 you can tell that 2,320,000,000 is longer just by looking at it, so you can determine that ....
232,000,000 = 2.32E8
2,320,000,000=2.32E9
Using the same method you can solve the last two.
0.00000431 is a larger number than 0.000000000000431. So you can then determine that.....
0.00000431= 4.31E-6
0.000000000000431=4.31E-13
To begin with, let us look at a few definitions that will help
A relation is a function if each x-value is paired with exactly one y-value. A vertical line test on a graph can be used to determine whether a relation is a function.
If we use a graph to check, we will have
We can see that there is no overlapping of coordinates. The table satisfies the vertical line test.
Hence, it is a function
The domain and range of function is the set of all possible inputs and outputs of a function respectively. The domain and range of a function y = f(x) is given as domain= {x ,x∈R }, range= {f(x), x∈Domain}.
The domain of the function, D is given by

The range, R is given by
Answer:
1/2
Step-by-step explanation:
The lecture has already begun when the student arrives means one of these scenarios happen:
1) the class started at 5:10 and the student arrives at 5:11 or 5:12 or 5:13 or 5:14
2) the class started at 5:11 and the student arrives at 5:12 or 5:13 or 5:14
3) the class started at 5:12 and the student arrives at 5:13 or 5:14
Given student time of arrival is uniformly distributed, then the probability he/she arrives at 5:09 or 5:10 or 5:11 or 5:12 or 5:13 or 5:14 is 1/6.
So, the probability that the student arrives between 5:11 and 5:14 is 1/6 + 1/6 + 1/6 + 1/6 = 2/3.
The probability that the student arrives between 5:12 and 5:14 is 1/6 + 1/6 + 1/6 = 1/2.
The probability that the student arrives at 5:13 or 5:14 is 1/6 + 1/6 = 1/3.
Given class starting time is uniformly distributed, then the probability it starts at 5:10 or 5:11 or 5:12 is 1/3.
Given the two events are independent, the probability of the first scenario is: (1/3)*(2/3) = 2/9
For the second scenario: (1/3)*(1/2) = 1/6
For the third scenario: (1/3)*(1/3) = 1/9
Because all of these scenarios are mutually exclusive the total probability of one of them happen is: 2/9 + 1/6 + 1/9 = 1/2
The correct answer would be : -2/5
I hope that this helps you !