Gary drew a rectangle with a perimeter of 12 inches. Then he tried to draw a square with a perimeter of 12 inches.

1 answer:

7 0

What is your question?
(Please don report me, im just trying to help, really)
If theres supposed to be a picture, i dont see anything btw.

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Tom has 12 ears of field corn to make

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Tom arranged 3 groups of 4

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What is 15% of 60? Create a model to prove your answer (this is the question. I didn't really understand today's lesson in class

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2 years ago

Mary walks 2 1/2 miles in the morning and 5 7/8 in the afternoon. how much is that in all?

Gre4nikov [31]

Answer: 8.375

Step-by-step explanation:

Add them together and turn them into a decimal, and you have ur answer!

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2 years ago

Sketch the region enclosed by y=3x and y=x^2 . Then find the area of the region.

kolezko [41]

Answer:

$A=4.5u^2$

Step-by-step explanation:

The integral of a function gives you the area under the curve, the subtraction of one of the areas from the other will give you the area in between.

The limits of integration are the points where the curves intersect each other(take the curves has a system of equation and solve for x and y):

$y=3x, y=x^2\\3x=x^2\\x^2-3x=0\\x(x-3)=0\\x_1=0\\x-3=0\\x_2=3$

$y_1=3x_1=3(0)=0\\y_2=3x_2=3(3)=9$

The integral will be the subtraction of the curve $y=3x$ and $y=x^2$ (In the graph you can see y=3x is the upper curve):

$\int\limits^3_0 {3x-x^2} \, dx =\left\frac{3x^2}{2}-\frac{x^3}{3}\right|^3_0=\frac{3(3)^2}{2}-\frac{(3)^3}{3}-\left(\frac{3(0)^2}{2}-\frac{(0)^3}{3}\right)\\\int\limits^3_0 {3x-x^2} \, dx =\frac{27}{2}-\frac{27}{3} =13.5-9=4.5u^2$

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2 years ago

The square root of 17 is between the what two whole numbers? (just list them with a comma in between them.)

siniylev [52]

Answer:

17 lies between 16 and 25. So√17 lies between √16 and √25. The prime factorization method is used to write a square root of a non-perfect square number in the simplest radical form.

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2 years ago

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