110 horses can be found in one day with 44 bales of hay. If each horse needs 2/5 bales of hay each day, just convert 2/5 into a decimal (0.4) and divide 44 by 0.4 to get 110. (That's a lot of horses!)
Step-by-step explanation:
the solution is found in the images above
It is Nonresponse. We can infer that the entire population cannot be made.
First make and equation. Since you want to find the number of the day where both charge the same total amount, you would make the equation:
let x= the number of days
110+46(x)=70+54(x)
Solve:
110-70+46(x)=70-70+54(x)
40+46(x)=54(x)
40+46(x)-46(x)=54(x)-46(x)
40=8(x)
40/8=8x/8
5=x
Therefore your answer would be 5 days
Dimensions of the rectangle (width and length) are 19 cm and 31 cm respectively.
Step-by-step explanation:
- Step 1: Given that the perimeter = 100 cm, let width be x cm and then length = 12 + x.
Perimeter of a rectangle = 2(length + width)
100 = 2(x + 12 + x)
100 = 4x + 24
4x = 100 - 24 = 76
∴ x = 76/4 = 19 cm
∴ Length = 19 + 12 = 31 cm
