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EastWind [94]
3 years ago
10

HELP PLZ ASAP WORTH XTRA POINTS!! INCLUDES SCREENSHOT

Mathematics
1 answer:
Rainbow [258]3 years ago
4 0

Answer:

99

Step-by-step explanation:

8x-13+7x-17=180( because stright angle = 180 degree)

15x-30=180

15x=210

x=14

8(14)-13= 99

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You triple your account balance by making a deposit. Then you withdraw $28.50 from your bank account. Now your account is overdr
Crazy boy [7]

Answer:

Your original account balance before you made the deposit is $6

Step-by-step explanation:

Let x = your original account balance.

You triple your account balance by making a deposit. This means

New account balance = 3 × x = 3x

Then you withdraw $28.50 from your bank account. This means that you have $(3x - 28.5) left.

Now your account is overdrawn by $10.50. This means you have withdrawn beyond what you have in your account. Your new account balance is -$10.5. Therefore,

3x - 28.5 = - 10.5

3x = -10.5 + 28.5 = 18

x = 18/3 = 6

Your original account balance before you made the deposit is $6

8 0
3 years ago
A rectangular paperboard measuring 29in long and 20in wide has a semicircle cut out of it, as shown below.
katen-ka-za [31]

Here, we are required to find the area of the paper board given after the semicircle is cut out of it

Area of the paper board thatremains is 423 in²

Length = 29 in

Width = 20 in

Area of a rectangle = length × width

= 29 in × 20 in

= 580 in²

Area of a semi circle = πr²/2

π = 3.14

r = diameter / 2 = 20 in / 2 = 10 in

Area of a semi circle = πr²/2

= 3.14 × (10 in)² / 2

= 3.14 × 100 in² / 2

= 314 in²/2

= 157 in²

The semicircle is cut out of the rectangle

Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle

Area of the paper board that remains = Area of a rectangle - Area of a semi circle

= 580 in² - 157 in²

= 423 in²

brainly.com/question/16994941

6 0
3 years ago
There are 143076 books in the library. The 3rd grade class walked over and each kid checked out 2 books. There are 21 students i
9966 [12]

Answer:

The answer is: There are only 143034 books left after the students return to their classroom

Step-by-step explanation:

Lets call X= Number of books left in the library after the students return to their classroom.

B=Total of Books in the library

S=Total of books taken by the 3rd grade students

If each student  of the 3rd grage class take 2 books, the total of book taken by the 3rd grade students would be:

S=2 books per student * Total of students of the 3rdgrade

S=2*21=42

Then we must substract Total of Books in the library minus Total of books taken by the 3rd grade students. That would be:

X=B-S

X=143076-42

X=143034

I hope that this answer will help you

7 0
3 years ago
Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod
goblinko [34]

(2+3)^{-1}\equiv5^{-1}\pmod7 is the number <em>L</em> such that

5L\equiv1\pmod7

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

2a\equiv1\pmod7\implies a\equiv4\pmod7

since 2*4 = 8, whose residue is 1 mod 7;

3b\equiv1\pmod7\implies b\equiv5\pmod7

which we got for free by finding the inverse of 5 earlier. So

2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7

and so <em>R</em> = 2.

Then <em>L</em> - <em>R</em> = 1.

6 0
3 years ago
What is the property that is shown?
Mazyrski [523]

opposite of a sum property

hope it helps

3 0
3 years ago
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