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Vinil7 [7]
3 years ago
12

Daniel got a traffic citation. He had the option of paying 30% of his fine for traffic school. If traffic school cost $240, how

much was the total fine for his traffic violation?
Mathematics
2 answers:
White raven [17]3 years ago
5 0
30% of the fine is $240

Let x = fine
.3x = 240 \\ x = 240  \div .3 \\ x = 800
The fine is $800
natita [175]3 years ago
4 0

30%=30/100=0,30

240x0,30=72      $72 total fine

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Answer:

\displaystyle P(A)=\frac{6}{11}

Step-by-step explanation:

<u>Probabilities</u>

The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.

Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is

\Omega=\{WW,WN,NW,NN\}

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\displaystyle \frac{5}{11}

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\displaystyle \frac{6}{10}

Thus the option WN has the probability

\displaystyle P(WN)=\frac{5}{11}\cdot \frac{6}{10}=\frac{30}{110}=\frac{3}{11}

Now for the second option NW. The initial probability to pick a non-white counter is

\displaystyle \frac{6}{11}

The probability to pick a white counter is

\displaystyle \frac{5}{10}

Thus the option NW has the probability

\displaystyle P(NW)=\frac{6}{11}\cdot \frac{5}{10}=\frac{30}{110}=\frac{3}{11}

The total probability of event A is the sum of both

\displaystyle P(A)=\frac{3}{11}+\frac{3}{11}=\frac{6}{11}

\boxed{\displaystyle P(A)=\frac{6}{11}}

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Step-by-step explanation:

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