Remember that -csc^2(x) is a known derivative; it is the derivative of cot(x).
<span>Keeping that in mind, let's put a negative there, and then offset it with another negative, which can conveniently be placed outside of the integral. </span>
<span>(-1) Integral ( -csc^2(x) dx ) </span>
<span>Which evaluates to </span>
<span>(-1) cot(x) + C </span>
<span>-cot(x) + C</span>
Answer:
C and G
Step-by-step explanation:
(x^2+4)^2+32=12x^2+48 is written as 
.
We can simplify the expression using the term a by replacing x^2 + 4 with a.
This factors into (a-4)(a-8). Solve by setting each factor equal to 0 and solve for a.
a-4 = 0 a=4
a-8=0 a=8
1.)
2.)
<em>Hope it helps and is useful :)</em>
Answer:
Hence after period of 9 years from 1990 t0 1999 will be 61438 rabbits.
Step-by-step explanation:
Given:
Population for rabbit obeys exponential law.
120 at 1990 and 240 1991 ...after 1 year time period
To Find:
After 9 year time period how many rabbits will be there.
Solution:
Exponential law goes on present value and various value and time period and defined as ,
let Y be present value Y0 previous year value and k exponential constant and t be time period.
So
Y=Y0e^(kt)
Here Y=240 ,Y0=120 t=1 year time period
So
240=120e^(k*1)
240/120=e^k
2=e^k
Now taking log on both side, [natural log]
ln(2)=ln(e^k)
ln(2)=kln(e)
k=ln(2)
k=0.6931
For t=9 year of time period
Y0=120, t=9 ,k=0.6931
Y=Y0e^(k*t)
Y=120*e^(0.6931*9)
=120e^6.2383
=61438.48
=61438 rabbits
Answer:
36894
Step-by-step explanation:
hope it helps
