3 years ago

What positive number x satisfies the equation 3x^2 = 27^3?

Mathematics

1 answer:

CaHeK987 [17]3 years ago

5 0

3x^2=27^3

Simplify both sides of the equation

3x^2=19683

Then divide both sides by three

x^2=6561

find square root

x=81

Hope this helped :)

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Given expression is $4 x \cdot \frac{1}{x^{-5}} \cdot x^{-3}$ .

To simplify the given expression.

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