Question

The first barn contained 3 times more hay than the second one. After 20 tons of hay were removed from the first barn and 20 tons were added to the second barn, the amount of hay in the second barn was 5/7 of the amount remaining in the first barn. How many tons of hay was there in each barn?

Answer 1

The solution would be like this for this specific problem:

 

a + 20 = 5/7 (3a - 20) 
a + 20 = (15a - 100)/7 
Multiply both side by 7, 
7a + 140 = 15a - 100 
8a = 240 
a = 30

3a = 90

a + 20 = 50

3a - 20 = 70

5/7 x 70 = 50

Answer 2

Answer:

90 in the first and 30 in the second for before and for after there is

70 in the first and 50 for the second.

Step-by-step explanation:

Before solution:

a+20=5/7(3a-20)

a+20=(15a-100)7

multiply each side by 7

7a+140=15a-100

8a=240

a=30

3a=90  

After solution (with information from last equation):

a+20=5/7(3a-20)

30+20=5/7(90-20)

50=5/7(70)

50=50

a=50

3a times 5/7=70