4 years ago

The overall charge of the nucleus is ______

Physics

1 answer:

Andrews [41]4 years ago

7 0

The answer in positive

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On a spacecraft, two engines are turned on for 684 s at a moment when the velocity of the craft has x and y components of v0x 43

Natasha2012 [34]

As we know by the kinematics

$\delta x = v_x * t + \frac{1}{2} at^2$

$4.11106 = 4370* 684 + \frac{1}{2}a_x*684^2$

$4.11106 = 2989080 + 233928*a_x$

$a_x = -12.78 m/s^2$

Similarly for Y direction

$\delta y = v_y * t + \frac{1}{2} at^2$

$6.07106 = 6280* 684 + \frac{1}{2}a_y*684^2$

$6.07106 = 4295520 + 233928*a_y$

$a_y = -18.36 m/s^2$

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What is t = 0 s and t = 8 s?

Deffense [45]

Answer:

t=0 is t

t=8= 8t

Explanation:

because 0 is means "nothing" so that's why t=0 is t

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3 years ago

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Mnenie [13.5K]

Velocity= 1/4 = 0.25 m/s towards the ball

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3 years ago

A baseball is thrown horizontally from a cliff at 30 m/s and lands 7 seconds after the baseball was thrown. Calculate the horizo

ASHA 777 [7]

Answer:

The horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively.

Explanation:

Using the equation of the displacement in the x-direction, we have:

(let's recall we have a constant velocity in this direction)

$x=v_{ix}t$

Where:

v(ix) is the initil velocity in the x direction (v(ix) = 30 m/s)
t is the time (t = 7 s)

$x=30(7)$

$x=210\: m$

Now, we need to use the equation of the displacement in the y-direction to find the vertical distance. Here we have an acceleration (g)

$y=v_{iy}t-\frac{1}{2}gt^2$

Where:

v(iy) is the initial velocity at the y-direction. In this case, it will be 0
t is the time
g is the acceleration of gravity (g=9.81 m/s²)

Then, the vertical position at 7 s is:

$y=-\frac{1}{2}(9.81)(7)^2$

$y=-240.35\: m$

Therefore, the horizontal and vertical distances are x = 210 m and y = -240.35 m, respectively. The minus sign means the <u>negative value in the y-direction.</u>

I hope it helps you!

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3 years ago