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FromTheMoon [43]
1 year ago
11

A nonconducting sphere of radius r0 carries a total charge q distributed uniformly throughout its volume

Physics
1 answer:
Angelina_Jolie [31]1 year ago
8 0

The electric field for the nonconducting sphere of radius r₀ carries a total charge q distributed uniformly throughout its volume will be,E=kQ\frac{r}{r_0^3}.

<h3 /><h3>What is an electric field?</h3>

It is a physical field occupied by a charged particle on another particle in its surrounding.

For a non-conducting sphere, the charge density is;

\rm \rho = \frac{q}{V} \\\\ \rho = \frac{Q}{\frac{4}{3}\pi r^3 } \\\\ \rho = \frac{3Q}{4 \pi r_0^3} \\\\

The electric field is found as;

\rm E=K \frac{\rho V}{r^2} \\\\ E= k \frac{3Q \times 4 \pi r^3}{4 \pi r_0^3 \times 3r^2} \\\\ E=kQ\frac{r}{r_0^3}

Hence, the electric field for the nonconducting sphere of radius r₀ carries a total charge q distributed uniformly throughout its volume will be,E=kQ\frac{r}{r_0^3}.

To learn more about the electric field, refer to the link;

brainly.com/question/26690770

#SPJ4

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Lady_Fox [76]

Answer:

Explanation:

For sound level in decibel scale the relation is

dB = 10 log I / I₀ where I₀ = 10⁻¹² and I is intensity of sound whose decibel scale is to be calculated .

Putting the given values

61 = 10 log I / 10⁻¹²

log I / 10⁻¹² = 6.1

I = 10⁻¹² x 10⁶°¹

=10^{-5.9}

intensity of sound of 5 persons

I=5\times 10^{-5.9}

dB=10log\frac{5 X 10^{-5.9}}{10^{-12}}

= 10log 5 x 10⁶°¹

= 10( 6.1 + log 5 )

= 67.98

sound level will be 67.98 dB .

4 0
2 years ago
Which nucleus completes the following equation?<br> A. 299 Np<br> B. 20Pa<br> C. 2 Pa<br> D. - Np
blondinia [14]

Answer:

Option D. ²³⁹₉₃Np

Explanation:

Let the unknown be ʸₓA.

Thus, the equation becomes:

²³⁹₉₂U —> ⁰₋₁e + ʸₓA

Next, we shall determine the x, y and A. This can be obtained as follow:

92 = –1 + x

Collect like terms

92 + 1 = x

93 = x

x = 93

239 = 0 + y

239 = y

y = 239

ʸₓA => ²³⁹₉₃A => ²³⁹₉₃Np

Thus, the complete equation is:

²³⁹₉₂U —> ⁰₋₁e + ²³⁹₉₃Np

7 0
3 years ago
two electronics students are discussing electrical units. student A says that electrical power is measured in units coulombs, st
Savatey [412]
The statements of both students are incorrect.

-- Electrical power, just like mechanical power, is expressed in units of watts.
-- 'Coulomb' is the unit of electrical charge.
-- '400 k ohms'  means 400,000 ohms of resistance.
-- 'Volt' is the unit of electromotive force (or potential difference).

There are no 'following statements'.

All in all, a very disappointing question.

8 0
2 years ago
You are tossing a ball directly up into the air. Before the ball leaves your hand, you are exerting a force directed against the
DaniilM [7]

Answer:

F n = 0.2 N

Explanation:

given,                                      

you are exerting force of 10 N on the ball.

mass of the ball = 1 kg              

acceleration due to gravity  = 9.8 m/s²

normal force on the ball = ?          

normal force is force exerted by the object to counteract the force from other object.                

normal force acting on the ball will be

F n = F - mg                          

F n = 10 - 1 × 9.8                        

F n = 10 -9.8                    

F n = 0.2 N            

Hence, normal force acting on the ball is equal to 0.2 N

7 0
3 years ago
The length of a simple pendulum is 0.81 mand the mass of the particle (the "bob") at the end of the cable is0.23 kg. The pendulu
Gemiola [76]

Answer:

\displaystyle w=3.478\ rad/sec

M=0.0182\ J

v=0.398\ m/s

Explanation:

<u>Simple Pendulum</u>

It's a simple device constructed with a mass (bob) tied to the end of an inextensible rope of length L and let swing back and forth at small angles. The movement is referred to as Simple Harmonic Motion (SHM).

(a) The angular frequency of the motion is computed as

\displaystyle w=\sqrt{\frac{g}{L}}

We have the length of the pendulum is L=0.81 meters, then we have

\displaystyle w=\sqrt{\frac{9.8}{0.81}}

\displaystyle w=3.478\ rad/sec

(b) The total mechanical energy is computed as the sum of the kinetic energy K and the potential energy U. At its highest point, the kinetic energy is zero, so the mechanical energy is pure potential energy, which is computed as

U=mgh

where h is measured to the reference level (the lowest point). Please check the figure below, to see the desired height is denoted as Y. We know that

H+Y=L

And

H=L\ cos\alpha

Solving for Y

Y=L(1-cos\alpha )

Since\ \alpha=8.1^o, L=0.81\ m

Y=0.0081\ m

The potential energy is

U=mgh=0.23\ kg(9.8\ m/s^2)(0.0081\ m)

U=0.0182\ J

The mechanical energy is, then

M=K+U=0+U=U

M=0.0182\ J

(c) The maximum speed is achieved when it passes through the lowest point (the reference for h=0), so the mechanical energy becomes all kinetic energy (K). We know

\displaystyle K=\frac{mv^2}{2}

Equating to the mechanical energy of the system (M)

\displaystyle \frac{mv^2}{2}=0.0182

Solving for v

\displaystyle v=\sqrt{\frac{(2)(0.0182)}{0.23}}

v=0.398\ m/s

4 0
3 years ago
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