Hello,
I believe it is true.
Hope this helped!
Answer:
b = -2c ± [√(4π²c² + πA)]/π
Step-by-step explanation:
A = 4πbc + πb^2
A = 4πbc + πb²
πb² + 4πbc - A = 0
Using the quadratic formula to solve this quadratic equation.
The quadratic formula for the quadratic equation, pb² + qb + r = 0, is given as
b = [-q ± √(q² - 4pr)] ÷ 2p
Comparing
πb² + 4πbc - A = 0 with pb² + qb + r = 0,
p = π
q = 4πc
r = -A
b = [-q ± √(q² - 4pr)] ÷ 2p
b = {-4πc ± √[(4πc)² - 4(π)(-A)]} ÷ 2π
b = {-4πc ± √[16π²c² + 4πA]} ÷ 2π
b = (-4πc/2π) ± {√[16π²c² + 4πA] ÷ 2π}
b = -2c ± [√(4π²c² + πA)]/π
Hope this Helps!!!
I think the answer is Q = -3
Answer:
x + 18 ≥ 26
Step-by-step explanation:
"greater than or equals": ≥
x + 18 ≥ 26 is your answer.
If you are trying to solve it so you isolate x, subtract 18 from both sides:
x + 18 (-18) ≥ 26 (-18)
x ≥ 26 - 18
x ≥ 8
x ≥ 8 is your answer.
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The answer is B f(x)= -3(x+1)^2+2
