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crimeas [40]
3 years ago
11

Item 18 A spherical ball with a volume of 972π in.3 is packaged in a box that is in the shape of a cube. The edge length of the

box is equal to the diameter of the ball. What is the volume of the box?

Mathematics
1 answer:
alexandr402 [8]3 years ago
3 0
Check the picture below.

so, the diameter of the sphere, is the same as a side's length of the cube, bearing in mind that all sides in a cube are the same length.

since all sides in the cube are "d", then its volume is V = d*d*d or V = d³.

\bf \textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}~~
\begin{cases}
r=radius\\
-----\\
V=972\pi 
\end{cases}\implies 972\pi =\cfrac{4\pi r^3}{3}\implies 2916\pi =4\pi r^3
\\\\\\
\cfrac{2916\pi }{4\pi }=r^3\implies 729=r^3\implies \sqrt[3]{729}=r\implies \boxed{9=r}

since the diameter is twice as much as the radius, thus d = 2r, or namely d = 18.

therefore, the volume of the cube will be V = 18³.

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