Answer: 5 to the 3rd times 3 to the second times 2
Step-by-step explanation:
I think it eould be 17 feet. 5 plus 8 plus 4 is 17.
Answer:
The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
Sample of 421 new car buyers, 75 preferred foreign cars. So ![n = 421, \pi = \frac{75}{421} = 0.178](https://tex.z-dn.net/?f=n%20%3D%20421%2C%20%5Cpi%20%3D%20%5Cfrac%7B75%7D%7B421%7D%20%3D%200.178)
85% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.151](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.178%20-%201.44%5Csqrt%7B%5Cfrac%7B0.178%2A0.822%7D%7B421%7D%7D%20%3D%200.151)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.205](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.178%20%2B%201.44%5Csqrt%7B%5Cfrac%7B0.178%2A0.822%7D%7B421%7D%7D%20%3D%200.205)
The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).
The net decrease in calories after walking for 5 hours is 50 calorie.
According to the statement
we have given that the
A 25-year old woman burns 200−20t cal/hr and Her caloric intake from drinking Gatorade is 110t calories during the t hour.
And we have to find the net decrease in calories after walking for 5 hours.
So, For this purpose,
We know that the
calories burns in one hour = 200−20t
calories burns in 5 hours = 5(200−20t)
calories burns in 5 hours = 1000 - 100t
Now,
Calorie intake in t hours = 110t
And
net decrease in calories after walking for 5 hours = 100t - 1000 + 110t
put t is 5 then
net decrease in calories after walking for 5 hours = 210(5) - 1000
net decrease is 50 cal.
So, The net decrease in calories after walking for 5 hours is 50 calorie.
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