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SpyIntel [72]
3 years ago
10

20 POINTS FOR WHOEVER ANSWERS FIRST-

Mathematics
1 answer:
Komok [63]3 years ago
4 0
Okay so you take the number of weekdays to the number of weekends the ratio is 5:2 one month, which usually has 30 days which is 4 weeks tops so that is about 21 week days and and 9 weekends then times both by 12 you get 108 weekends and 252 weekdays i know that only equals 360 but this is a rough estimate so write that as a fraction 3/7 so there is a third that it will be on a weekday 
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Step-by-step explanation:

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Step-by-step explanation:

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Marizza181 [45]

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5 0
3 years ago
Find the length of diagonal HJ. Round to the nearest hundredth.
Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}, where

 (x_{1},y_{1}) and (x_{2},y_{2}) are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ x_{1}=-4 and x_{2}=5

∴ y_{1}=3 and y_{2}=-3

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = \sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}

∴ HJ = \sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0
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