The value of f(5) is 49.1
Step-by-step explanation:
To find f(x) from f'(x) use the integration
f(x) = ∫ f'(x)
1. Find The integration of f'(x) with the constant term
2. Substitute x by 1 and f(x) by π to find the constant term
3. Write the differential function f(x) and substitute x by 5 to find f(5)
∵ f'(x) = + 6
- Change the root to fraction power
∵ =
∴ f'(x) = + 6
∴ f(x) = ∫ + 6
- In integration add the power by 1 and divide the coefficient by the
new power and insert x with the constant term
∴ f(x) = + 6x + c
- c is the constant of integration
∵
∴ f(x) = + 6x + c
- To find c substitute x by 1 and f(x) by π
∴ π = + 6(1) + c
∴ π = + 6 + c
∴ π = 6.4 + c
- Subtract 6.4 from both sides
∴ c = - 3.2584
∴ f(x) = + 6x - 3.2584
To find f(5) Substitute x by 5
∵ x = 5
∴ f(5) = + 6(5) - 3.2584
∴ f(5) = 49.1
V = l • w • h
V = 10 • 18 • 3
V = 540 in cubed
Answer:
x = -2
Step-by-step explanation:
![f(x) =x^2 -2x\:\: and \:\: g(x) = 6x + 4\\(f+g)(x) = f(x) + g(x) \\(f+g)(x) = x^2 -2x+ 6x + 4\\(f+g)(x) = x^2+4x + 4\\(f+g)(x) = (x+2)^2\\ 0 = (x+2)^2...[\because (f+g)(x) =0]\\0 = x+2\\\therefore x = -2](https://tex.z-dn.net/?f=f%28x%29%20%3Dx%5E2%20-2x%5C%3A%5C%3A%20and%20%5C%3A%5C%3A%20g%28x%29%20%3D%206x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%28f%2Bg%29%28x%29%20%3D%20x%5E2%20-2x%2B%206x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20x%5E2%2B4x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20%28x%2B2%29%5E2%5C%5C%200%20%3D%20%28x%2B2%29%5E2...%5B%5Cbecause%20%28f%2Bg%29%28x%29%20%3D0%5D%5C%5C0%20%3D%20x%2B2%5C%5C%5Ctherefore%20x%20%3D%20-2)
