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Dima020 [189]
4 years ago
6

Johnny is booking a band and a DJ for a dance, and wants to keep the cost of the entertainment under $750. A band can play for p

art of the time at an hourly rate of $140, and a DJ can play for the remaining time at an hourly rate of $89. Write the inequality in standard form that describes this situation. Use the given numbers and the following variables. x = the number of hours the band will play y = the number of hours the DJ will play
Mathematics
1 answer:
Vsevolod [243]4 years ago
8 0
The equation for this problem is 140x+89y<750.
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svetlana [45]
X = 24
y = 45


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3 years ago
Combine like terms 45Y +13 Y equals
Leya [2.2K]

Answer:

45Y + 13Y equals 58Y is the answer

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3 years ago
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PLEASE HELP!! Puzzle One
Elina [12.6K]
The answer is possibly is B
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3 years ago
Jenna mixed two shades of purple paint. For Purple People Eater, she used 3 pints of red paint for every 5 pints of blue paint.
emmasim [6.3K]

Answer:

\frac{12}{35}

Step-by-step explanation:

Given :

→ For Purple People Eater, she used 3 pints of red paint for every 5 pints of blue paint.

i.e, The ratio of red paint to blue paint is 3:5

→ For Purple Majesty, she used a blue to red paint ratio of 7 to 4.

i.e, The ratio of red paint to blue paint is 4:7

To find :

1) Compare the ratios of red paint to blue paint.

\frac{3}{5}\times \frac{4}{7}=\frac{12}{35}

2) The ratio for Purple People Eater can be expressed in fraction form as :

=\frac{3}{5}

3) The ratio for Purple Majesty can be expressed in fraction form as :

=\frac{7}{4}

4) To compare these fractions, rewrite them with a common denominator

For common denominator

Multiply numerator and denominator by 4 in \frac{3}{5}

\Rightarrow\frac{3\times 4}{5\times4}=\frac{12}{20}

Multiply numerator and denominator by 5 in \frac{7}{4}

\Rightarrow\frac{7\times 5}{5\times4}=\frac{35}{20}

Common denominator is 20


6 0
3 years ago
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Match each spherical volume to the largest cross sectional area of that sphere
zlopas [31]

Answer:

Part 1) 324\pi\ units^{2} ------> 7,776\pi\ units^{3}

Part 2) 36\pi\ units^{2} ------> 288\pi\ units^{3}

Part 3) 81\pi\ units^{2} ------> 972\pi\ units^{3}

Part 4) 144\pi\ units^{2} ------> 2,304\pi\ units^{3}

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

A=324\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

324\pi=\pi r^{2}

Solve for r

r^{2}=324

r=18\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=18\ units

substitute

V=\frac{4}{3}\pi (18)^{3}

V=7,776\pi\ units^{3}

Part 2) we have

A=36\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

36\pi=\pi r^{2}

Solve for r

r^{2}=36

r=6\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=6\ units

substitute

V=\frac{4}{3}\pi (6)^{3}

V=288\pi\ units^{3}

Part 3) we have

A=81\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

81\pi=\pi r^{2}

Solve for r

r^{2}=81

r=9\ units

Find the volume of the sphere

The volume of the sphere is

V=\frac{4}{3}\pi r^{3}

For r=9\ units

substitute

V=\frac{4}{3}\pi (9)^{3}

V=972\pi\ units^{3}

Part 4) we have

A=144\pi\ units^{2}

The area of the circle is equal to

A=\pi r^{2}

so

144\pi=\pi r^{2}

Solve for r

r^{2}=144

r=12\ units

Find the volume of the sphere

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V=\frac{4}{3}\pi r^{3}

For r=12\ units

substitute

V=\frac{4}{3}\pi (12)^{3}

V=2,304\pi\ units^{3}

5 0
3 years ago
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