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Mice21 [21]
3 years ago
8

Complete the square to solve 2x^2+20x=1 0

Mathematics
1 answer:
serious [3.7K]3 years ago
5 0

Answer:

Step-by-step explanation:

Step 1: Subtract 10 from both sides.

2x2+20x−10=10−10

2x2+20x−10=0

For this equation: a=2, b=20, c=-10

2x2+20x+−10=0

Step 2: Use quadratic formula with a=2, b=20, c=-10.

x=

−b±√b2−4ac

2a

x=

−(20)±√(20)2−4(2)(−10)

2(2)

x=

−(20)±√(20)2−4(2)(−10)

2(2)

x=

−20±√480

4

x=−5+√30 or x=−5−√30

Answer:

x=−5+√30 or x=−5−√30

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Which of the following could NOT be the lengths of the sides of a triangle?
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Given:

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To find:

Which could NOT be the lengths of the sides of a triangle.

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