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3 years ago

How did the movement of sunspots on the surface of the sun affect peoples' beliefs about astronomy at the time?

Mathematics

1 answer:

lbvjy [14]3 years ago

4 0

Answer:

is this science?

Step-by-step explanation:

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A partir del término general, calcular los 4 primerostérminos. (Considere que debe asignar

Scorpion4ik [409]

Answer:

$4,7,12,19,...$

Step-by-step explanation:

The question in English is:

From the general term, calculate the first 4 terms.

(Consider that you must assign values to the variable n)

we have

$b_n=n^2+3$

step 1

Calculate the first term

For n=1

$b_1=(1)^2+3=4$

step 2

Calculate the second term

For n=2

$b_2=(2)^2+3=7$

step 3

Calculate the third term

For n=3

$b_3=(3)^2+3=12$

step 4

Calculate the fourth term

For n=4

$b_4=(4)^2+3=19$

therefore

the first 4 terms are

$4,7,12,19,...$

4 0

3 years ago

Lily and violet live 30 miles apart on a trail. They both start running towards each other with a plan to meet. Lily is moving a

erastovalidia [21]

Answer:

3 hours

Step-by-step explanation:

8 0

2 years ago

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .