Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
________________________________
now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
you given me only 25 point
0.0055 gram
I think that’s the right answer
Step-by-step explanation:
2/5 ÷ 8/15
2/5 × 15/8
=3/4
Hope it helps ya
Given:
The function is:

To find:
The inverse of the given function, then draw the graphs of function and its inverse.
Solution:
We have,

Step 1: Substitute
.

Step 2: Interchange x and y.

Step 3: Isolate variable y.


Step 4: Substitute
.

Therefore, the inverse of the given function is
and the graphs of these functions are shown below.
Note: The inverse function is
.