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Kryger [21]
3 years ago
9

A 9 cm tall cone shaped paper cup can hold up to 58.9 cm3 of water. What is the minimum amount of paper needed to make the paper

cup, assuming no overlap in the paper? Use 3.14 for π.
Mathematics
2 answers:
IgorC [24]3 years ago
8 0
Volume of cone is given by:
V=1/3πr²h
thus the radius of the cone will be:
58.9=1/3×3.14×r²×9
r²=6.25265
r~2.5 cm
thus the area of the cone will be:
A=πr(r+√(h²+r²))
A=3.14×2.5(2.5+√(2.5²+9²))
A=92.9500 cm²
Thus the area of material needed  to make the cup is 92.95 cm²

Naily [24]3 years ago
3 0

Answer:

A minimum of 93 cm squared

Step-by-step explanation:

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VladimirAG [237]
<h3>Answer: B) 31.348</h3>

======================================

Work Shown:

We will never use the alpha = 0.05 value when computing the test statistic. So we can ignore alpha for this particular problem.

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n = 40 is the sample size.

s = 2.6 is the sample standard deviation

\sigma = sigma = 2.9 is the population standard deviation (ie the claimed standard deviation for all the pay phones)

Test Statistic for chi-square

\chi^2 = \frac{(n-1)*s^2}{\sigma^2}\\\\\chi^2 = \frac{(40-1)*(2.6)^2}{(2.9)^2}\\\\\chi^2 = \frac{39*6.76}{8.41}\\\\\chi^2 = \frac{263.64}{8.41}\\\\\chi^2 \approx 31.3483947681332\\\\\chi^2 \approx 31.348\\\\

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