The way to work it is to make a table in Excel (or equivalent program) with the data of budget for every year.
This is how it should look:
<span><span><span>year
budget
</span>
<span>
0
265.1
</span>
<span>
1
277.5
</span>
<span>
2
288.9
</span>
<span>
3
303.0
</span>
<span>
4
311.3
</span><span> 5
320.4
</span><span> 6
334.5
</span><span> 7
351.2
</span>
<span>
8
368.2
</span>
<span>
9 381.7
Select both columns and inser a scatter plot graph (menu, insert, graph, scatterplot).
Now change the design of the graph to include the model. In this case I got y = 12.724 x + 262.92
x represents the number of year after 1990 and y represents the budget.
Now you can use the model to calcualte the budget when you know the year and to calculate the year when you know the budget.
For year 2001, x = 11 and y = 12.724 (11) + 262. 92 = 402.88 (which is 402,880)
This is the same year for which the budget exceeds 400,000. </span></span></span>
Answer:
you will need to find the difference (subtract) between two of the y points then do the same for the x points and put to difference of y on top of x and there is you slope using a graph( or if eaven, will come put as a whole number
(3x-12)+12(xy-10), x=4, y=6
(3(4)-12)+12((4)(6)-10)
(12-12)+12(24-10)
0+12(14)
12*14=168
Step-by-step explanation:
For the 1st picture,
The 2nd option is the answer.
Let say we have
Replace it into the recursive formula.
We are given a,1 and a,2 so the 3rd terms has to be
So the second option is the answer.
For the second picture, a geometric sequence is a group of terms that has the same ratio between each consecutively.
Infinite means going on forever
The fourth option is the answer.
