Find the diameter of a cone that has a volume of 83.74 cubic inches and a height of 5 inches. Use 3.14 for pi.

1 answer:

7 0

Start with V=(1/3)x(3.14)x(r-squared)x(h) This is the formula for the volume of a cone

Then plug in the values that you are given in the equation 83.74=(1/3)x(3.14)x(r-squared)x(5 inches)

Now combine "like terms" 83.74=(5.233333)x(r-squared)

Next you want to get "r" by itself, so by using order of operations we divide by 5.233333 on both sides and then you are left with 16=r-squared

Now to get rid of the "squared" you find the square root of both sides and you're left with 4=r

Now that you have the radius and the question is "what is the diameter" simply double the radius and so you are left with 8

The answer is 8 inches

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Maria is using a coordinate plane with the axes labeled only with integers. She says that the point (−0.5, 2) cannot be plotted

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Integers ={Positive Natuaral Number +Natural numbers having negative sign behind it+Zero}

={------,-3,-2,-1,0,1,2,3,..........}

→Points marked on the X and Y axis on the Coordinate Plane=Integers only

→Point to be marked on the coordinate plane =(-0.5,2)

→As, points on both X and Y axis are integers only.To mark, -0.5 , mark a line between , 0 and -1,that will be ,-0.5.

→You can mark , any terminating decimal on the number line, which is marked with integers only.

→Terminating decimals are those decimals having $2^a ,\text{or}5^b, \text{or} 2^a \times 5^b$ in the denominator of a fraction.

So, to plot any terminating Decimal on the coordinate plane, you have to use property of Rational Numbers ,which is, you can find infinite number of terminating Decimal between two terminating Decimal.

→Mark -0.5 between 0 and -1 on the X axis.Similarly, mark integer 2 on the Y axis.Draw a line parallel to Y axis ,passing from (-0.5,0) and line parallel to X axis passing through (0,2).The intersection of these two lines will be required point (-0.5,2).