Answer:
Bar will not fit in the box.
Step-by-step explanation:
Given:
Length = 9 in
Width = 8 in
Height = 3 in
Length of bar = 13 in
Find:
Bar fit in box or not
Computation:
If length of bar is equal to length of diagonal than it will fit in box.
Diagonal of a cuboid = √l² + b² + h²
Diagonal of a cuboid = √9² + 8² + 3²
Diagonal of a cuboid = √81 + 64 + 9
Diagonal of a cuboid = √154
Diagonal of a cuboid = 12.40 in
Diagonal of a cuboid < Length of bar
So,
Bar will not fit in the box.
Answer:
○ C) 256 in.²
Step-by-step explanation:
{a}^{2} + 2a \sqrt{ \frac{ {a}^{2}}{4} + {h}^{2} } = S. A. \\ \\ {8}^{2} + 2(8) \sqrt{ \frac{{8}^{2}}{4} + {12}^{2}} = 64 + 64\sqrt{10}\\ \\ 64\sqrt{10} ≈ 266,3857703 ≈ 256
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Answer:
Step-by-step explanation:
3 × 2 + x = 10
6 + x = 10
x = 10 -6
x = 4
Answer:
Step-by-step explanation:
y=mx+b -- m = slope, b = y-int
Given:
Cost of two donuts and three cookies = $3.30
Cost of five donuts and two cookies = $4.95
To find:
The cost of each donut.
Solution:
Let x be the cost of each donut and y be the cost of each cookie.
Cost of two donuts and three cookies = $3.30
...(i)
Cost of five donuts and two cookies = $4.95
...(ii)
Multiply equation (i) by 2.
...(iii)
Multiply equation (ii) by 3.
...(iv)
Subtracting (iii) from (iv), we get
Divide both sides by 11.
Therefore, the cost of each donut is $0.75.
