The sides of a triangle measure 6 inches 8 inches, and 10 inches. The triangle has one 90° angle. What type of triangle is it?

Add. Your answer should be a polynomial in standard form. ( − 8 y 2 − 9 y ) + ( 8 y 3 + 9 y 2 − 2 y ) =

aliya0001 [1]

(−8* y^2−9*y)+(8*y^3+9*y^2−2*y)
first, remove extraneous parentheses (or distribute if negative)
=−8* y^2−9*y+8*y^3+9*y^2−2*y
then group terms in decreasing degree of y (variable)
=+8*y^3 −8* y^2+9*y^2 −9*y−2*y
simply expression by adding/subtracting similar terms
=+8*y^3 +y^2 −11*y
to give the final answer.

6 0

3 years ago

Write an equation for the translation of y = |x|.

lana66690 [7]

B. To translate up or down the number must be outside of the absolute value bars

6 0

3 years ago

Two brands of AAA batteries are tested in order to compare their voltage. The data summary can be found below.

garik1379 [7]

Answer:

The 95% confidence interval would be given by $0.281 \leq \mu_1 -\mu_2 \leq 0.529$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =9.2$ represent the sample mean 1

$\bar X_2 =8.8$ represent the sample mean 2

n1=27 represent the sample 1 size

n2=30 represent the sample 2 size

$\sigma_1 =0.3$ population standard deviation for sample 1

$\sigma_2 =0.1$ population standard deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =9.2-8.8=0.4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $t_{\alpha/2}=1.96$

Now we have everything in order to replace into formula (1):

$0.4-1.96\sqrt{\frac{0.3^2}{27}+\frac{0.1^2}{30}}=0.281$

$0.4+1.96\sqrt{\frac{6^2}{36}+\frac{7^}{49}}=0.519$

So on this case the 95% confidence interval would be given by $0.281 \leq \mu_1 -\mu_2 \leq 0.529$

6 0

3 years ago

There is a spinner with 14 equal areas, numbered 1 through 14. If the spinner is spun one time, what is the probability that the

algol13

The probability is 3/14. There are 2 multiples of 4 in 14, which is 8 and 12. There is only 1 multiple of 6 in 14 which is 12. 1+2=3. It is possible outcomes over total outcomes so 3/14.

6 0

3 years ago

Read 2 more answers

in a round robin tennis tournament involving 7 players, each player will play every other player twice. How many total matches w

baherus [9]

Total number of ways to make a pair:

The first player can be any one of 7 . For each of those . . .
The opponent can be any one of the remaining 6 .

Total ways to make a pair = 7 x 6 = 42 ways .

BUT ... every pair can be made in two ways ... A vs B or B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.

If every pair plays 2 matches, then (21 x 2) = <em><u>42 total matches</u></em> will be played.

Now, is that an elegant solution or what !

8 0

3 years ago