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GarryVolchara [31]
3 years ago
8

A group of students is performing in experiment with so each student and 3/8 teaspoon of salt to a solution the group only has a

1/8 teaspoon Measuring spoon down many times were so cramped need to fill the measuring spoon in order to perform the experiment

Mathematics
1 answer:
hodyreva [135]3 years ago
6 0

Answer:

12 times.

Step-by-step explanation:

Attached is the complete question.

Given: Each student must add 3/8 teaspoon of salt to a solution.

           The group only has a 1/8 teaspoon measuring spoon.

Lets assume number of times spoon each students need to fill be "x" to get \frac{3}{8} \ teaspoon for performing experiment.

Now finding the number of times each students need to fill the measuring spoon.

⇒ \frac{1}{8} \times x= \frac{3}{8}

Multiplying both side by 8

⇒ x= \frac{3\times 8}{8}= 3

∴ x= 3 .

Hence, each students need to fill 3 times teaspoon to perform experiment.

As given there are 4 students in the group, therefore each will add 3 teaspoon to perform experiment.

∴ Total number of times teaspoon to be added = number\ of\ spoon\ by\ each\ student\times total\ number\ of\ students

Total number of teaspoon to be added= 3\times 4= 12

∴ 12 number of times teaspoon need to fill the measuring spoon in order to perform experiment.

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3 years ago
List five rational numbers between -4/5 and -2/3 . Please tell by step by step explaintion ​
attashe74 [19]

9514 1404 393

Answer:

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Step-by-step explanation:

There are an infinite number of ways to do this.

Perhaps the simplest is to do it in decimal.

 -4/5 = -0.8

  -2/3 = -0.666... (repeating 6)

Any negative decimal number between these values will do. For example, ...

  -0.67, -0.68, -0.69, -0.70, -0.71

__

If you want to choose fractions that are evenly spaced between the given values, you can find their difference, then divide that difference into 6 parts (1 more than the number of numbers you need).

  -2/3 -(-4/5) = 4/5 -2/3 = (12 -10)/(5·3) = 2/15 . . . . length of interval

  1/6 of this difference is ...

     (1/6)(2/15) = 2/90 = 1/45

The interval end point nearest 0 is ...

  -2/3 = -30/45

so the 5 intermediate values will be that value with -1/45 repeatedly added:

  -31/45, -32/45, -33/45 = -11/15, -34/45, -35/45 = -7/9

_____

<em>Additional comment</em>

The fractions we came up with could be referred to as "5 arithmetic means between -2/3 and -4/5." There is nothing in the problem statement suggesting the values need to be evenly spaced.

When doing this in decimal, you can obtain a new value simply by adding more digits to the decimal fraction:

  -0.68, -0.685, -0.6853, -0.68531, -0.799

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