Consider point P(x,y) such that P, X and Y are collinear,
As vectors
XP = XO + OZ where O(0,0)
XP = OZ - OX
XP= (x,y) - (-3,3)
XP = (x+3, y-3)
Similarly,
PY = (6-x, -3-y)
But XP= 2^PY
[x+3, y-3] = [2(6-x), 2(-3-y)]
Given both vectors are equal, as they go in the same direction, Solve for x and y accordingly:
x+3 = 12 - 2x
x = 3
y-3 = -6-2y
y = -1
Therefore, P(3,-1)
Answer:
first one : x=−2y−5z−17
2nd one: x=
3
/2
y−z−8
3rd one: x=
−1
/3
y+
1
/3
z+1
Step-by-step explanation:
Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
Part 1) Find the value of x
we know that
Triangles CDF and FDE are similar
therefore
The ratio of its corresponding sides is proportional and its corresponding angles are congruent
so
Part 2) Find the length of DE
substitute the value of x
The area is 19.5 and the perimeter is 23.1
Answer:
The answer is R(2).
Step-by-step explanation:
hope this helped!
