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slega [8]
3 years ago
6

ABCD is a square, what is the measure angle of BAC

Mathematics
2 answers:
Furkat [3]3 years ago
8 0
45 degrees, you are cutting the right angle in half
joja [24]3 years ago
8 0

Answer:

measure of ∠BAC  is  45°

Step-by-step explanation:

We have Square ABCD

we need to find the measure of ∠BAC

Let us take ΔBAC

We know that all the angles in a square is equal to  90°

Therefore ΔBAC is right angled triangle since  ∠ABC= 90°

Sum of angles in a triangle = 180°

∠ABC + ∠BCA + ∠BAC = 180°

90° + ∠BCA + ∠BAC =180°  ( since  ∠ABC= 90°)

∠BCA + ∠BAC =180° -90°  ( subtracting 90° from both sides)

∠BCA + ∠BAC = 90°

sides of square are equal so  AB = BC  and angles opposite to equal sides are equal hence ∠BCA = ∠BAC

so we have

∠BAC+∠BAC = 90°  

2∠BAC = 90°  

∠BAC = 45°   ( divide both sides by 2)

so we have measure of ∠BAC  is  45°  

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A number was subtracted from 15. After which, that result was multiplied by 5. This result was then divided by 5 for a result of
likoan [24]

Answer:

14

Step-by-step explanation:

15-14 = 1

1*5=5

5/1=1

6 0
2 years ago
The dot located in the middle of the segment
True [87]

If your asking for what that would be called cause I don't understand what your asking but it would be called the midpoint

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Why is my dad so mean to me?
Vladimir79 [104]
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Read 2 more answers
A frame is 6in tall and 8 in wide. What if it was reduced to a width of 4in then how tall will it be
kkurt [141]

Answer:

  3 in

Step-by-step explanation:

Apparently, we are to assume that the height and width are proportional:

  height/width = (6 in)/(8 in) = (new height)/(4 in)

Multiplying by 4 in will tell us the new height:

  new height = (4 in)(6/8) = 3 in

The reduced frame will be 3 inches tall.

6 0
2 years ago
NEED ANSWERED ASAP
fomenos
The answer is 10 2/3, 5

Proof:

Solve the following system:
{x/2 + y/3 = 7 | (equation 1)
{x/4 + (2 y)/3 = 6 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:
{x/2 + y/3 = 7 | (equation 1)
{0 x+y/2 = 5/2 | (equation 2)

Multiply equation 1 by 6:
{3 x + 2 y = 42 | (equation 1)
{0 x+y/2 = 5/2 | (equation 2)

Multiply equation 2 by 2:
{3 x + 2 y = 42 | (equation 1)
{0 x+y = 5 | (equation 2)

Subtract 2 × (equation 2) from equation 1:
{3 x+0 y = 32 | (equation 1)
{0 x+y = 5 | (equation 2)

Divide equation 1 by 3:
{x+0 y = 32/3 | (equation 1)
{0 x+y = 5 | (equation 2)
Collect results:
Answer: {x = 10 2/3, y = 5
8 0
3 years ago
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