Given:
t A = 2.4 h
t B = 4 h
v A = 22 + v B
Solution:
Distance A and distance B is the same, distance could be defined using formula d = v × t
d A = d B
(v A × t A) = (v B × t B)
plug in the numbers
v A × 2.4 = v B × 4
(22 + vB) × 2.4 = 4 vB
remove the parenthesis using distributive property
(22 × 2.4) + (2.4 × vB) = 4vB
52.8 + 2.4vB = 4vB
add like terms
52.8 = 4vB - 2.4vB
52.8 = 1.6vB
52.8/1.6 = vB
vB = 33
the speed of car B is 33 mph
vA = 22 + vB
vA = 22 + 33
vA = 55
the speed of car A is 55 mph
Answer:
y= −2/3x+−20/3
heart if it helped you brain if im cool
The answer should be 70 :)
Answer:
(-1,-2) OR x = -1 and y = -2
Step-by-step explanation:
y = 3x + 1
y = -x -3
so you would first multiply everything on y = -x -3 by 3 and get 3y = -3x -9
so then you would add 3y = -3x -9 to y = 3x + 1 (<u> to eliminate the x</u> )which would be 4y = -8 then divide by 4 and get <u><em>y = -2</em></u>
then you plug in y = -2 into any one of the equations but to make it easier i am going to plug it into y = -x -3 so now it would be -2 = -x - 3 then, add 2 to both sides which would be 0 = -x -1 then add 1 to both side 1 = -x then multiply both sides by -1 and get <u><em>x = -1</em></u>
<u><em>SO your answer would be </em></u> (-1,-2) OR x = -1 and y = -2 ( both of them are correct but it depends on what the teacher taught you)