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victus00 [196]
3 years ago
14

Un número entero de tres dígitos es igual a 25 veces la suma de sus dígitos. Si los tres dígitos se invierten, el número que res

ulta excede al número dado por 198.
El dígito de las decenas en uno menos que la suma de los dígitos de las centenas y de las unidades. Encuentra el número.
Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0
La repuesta es 375,porque 3+7+5 es 15,y 15x25 es 375. Tambien el digito de las decenas es uno menos que la suma de los digitos de las centenas y de las unidades.
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Please help asap I HV a time​
nikdorinn [45]

Answer: 382

Just add 300+70+12 and you get 382

8 0
3 years ago
Which of these situations can be represented with an integer​ that, when combined with the opposite of 8​, makes​ 0?
Lerok [7]
-8
On the number line if you are at positive 8 and add -8 you will lose 8 and get zero! Hope this helps!
6 0
1 year ago
Which shows the phrase "the product of a number and 3" as a variable expression?
JulijaS [17]

The algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z

<h3>How to write an algebraic expression for the word phrase "the product of a number and 3" as a variable expression?</h3>

The word phrase is given as:

"the product of a number and 3"

Represent the number with z

So, the word phrase can be rewritten as:

"the product of a number z and 3"

The product of a number z and 3 is represented as:

z * 3

When evaluated,, the expression becomes

z * 3 = 3z

Hence, the algebraic expression for the word phrase "the product of a number and 3" as a variable expression is 3z

Read more about algebraic expression at

brainly.com/question/4344214

#SPJ1

3 0
2 years ago
Find the surface Area. ​
kompoz [17]

Answer: 20

Step-by-step explanation: how i got the answer was to multiply everything by two. then add everything together.

3 0
3 years ago
The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff.
zhuklara [117]

\bf ~~~~~~\textit{initial velocity} \\\\ \begin{array}{llll} ~~~~~~\textit{in feet} \\\\ h(t) = -16t^2+v_ot+h_o \end{array} \quad \begin{cases} v_o=\stackrel{}{\textit{initial velocity of the object}}\\\\ h_o=\stackrel{}{\textit{initial height of the object}}\\\\ h=\stackrel{}{\textit{height of the object at "t" seconds}} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ h(t)=-16t^2+\stackrel{\stackrel{v_o}{\downarrow }}{19}t+110~\hspace{10em}19~\frac{ft}{sec}

3 0
3 years ago
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