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Alinara [238K]
3 years ago
8

Which angles intercept a 20° arc in a circle? Select all that apply.*A central angle of 10°*A central angle of 20°*A central ang

le of 40°*An inscribed angle of 10°*An inscribed angle of 20°*An inscribed angle of 40°​
Mathematics
1 answer:
melomori [17]3 years ago
3 0

We are asked to choose the angles that intercept a 20° arc in a circle.

We know that the measure of central angle is equal to the measure of its intercepted arc.

This means that a central angle with a measure of 20° will intercept to the our given arc. Therefore, option B is the correct choice.

We also know that the measure of inscribed angle is half the measure of its intercepted arc.

Let us find half of 20°.

\frac{20^{\circ}}{2}=10^{\circ}

This means that an inscribed angle with measure of 10° will intercept to the our given arc. Therefore, option D is the correct choice.

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a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
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0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that P(A) = 0.8

If you have passed subject A, the probability of passing subject B is 0.8.

This means that P(B|A) = 0.8

Find the probability that the student passes both subjects?

This is P(A \cap B). So

P(B|A) = \frac{P(A \cap B)}{P(A)}

P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

p = P(A) + P(B) - P(A \cap B)

Considering P(B) = 0.7, we have that:

p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86

0.86 = 86% probability that the student passes at least one of the two subjects

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3 years ago
Will someone pls help me?
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The width is 4x + 4

(4x)(2x) = 8x
(-3)(4) = 12
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2 years ago
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