Let x be the width of the sidewalk and the area becomes:
A=LW and L=6+2x and W=4+2x now we have
A=(6+2x)(4+2x) and we are told that A=48ft^2
48=24+20x+4x^2
4x^2+20x-24=0
4(x^2+5x-6)=0
x^2+5x-6=0
x^2-x+6x-6=0
x(x-1)+6(x-1)=0
(x+6)(x-1)=0
So x=-6, 1, however since x is a measurement it must be positive thus
x=width=1 ft is the only possible solution.
Answer:
see explanation
Step-by-step explanation:
(a)
Note the squared value in column 3 which is the square of 1 more than the row number, that is
row 2 → (2 + 1)² →3²
row 3 → (3 + 1)² → 4²
Find the square root of 676 = 26 → (25 + 1)² = 26²
Hence the row number is 25
(b)
The pattern in column 1 is [ row number × (row number + 2 ) + 1 ]
row number is n then n(n + 2) + 1 = n² + 2n + 1
Answer:
To find the horizontal asymptote, we note that the degree of the numerator is one and the degree of the denominator is two. Since the larger degree occurs in the denominator, the graph will have a horizontal asymptote at y = 0 (i.e., the x-axis). The vertical asymptotes will occur at those values of x for which the denominator is equal to zero.
Step-by-step explanation:
Answer:
-32
Step-by-step explanation:
B. 4/5
It would be 8/10 but you have to simplify it.
