Answer and Explanation:
The computation is shown below:
a. Current price is
= D1 ÷ (Required return - Growth rate)
= ($1.20 × 1.04 ÷ (0.1 - 0.04)
= $20.8
b. Now the price in three year is
P3 = Current price × (1 + Growth Rate)^3
= $20.8 × (1.04)^3
= $23.40
c. For price in 10 year it is
P10 = Current price × (1 + Growth Rate)^10
= $20.80 × (1.04)^10
= $30.79
We simply applied the above formula
Answer:
$56,000
Explanation:
Given the above information, we will calculate first the total cash flow.
Total cash flow = Opening cash receivable + Sales - Ending cash receivables
= $196,000 + $880,000 - $226,000
= $850,000
Ending cash balance = Opening cash balance + Total cash flow - Cash disbursement
= $146,000 + $850,000 - $940,000
= $56,000
In this scenario, Barry would be classified as a(n) <u>A. aggressive</u> salesperson.
<u>Explanation</u>:
Barry works for a popular radio station as a sales representative. From his conversation in the above scenario it is clear that Barry is an aggressive salesperson.
One day Barry was discussing with the marketing manager of a larger retail store regarding their new ad program. Barry was clear that the ad will be broadcasted around the clock all over the town if they agree with their radio station. He told that the ad will be aired day after tomorrow if the manager is ready to sign today.
a) Four inequalities
- Variables:
number of adult tickets = a
number of student tickets = s
- An adult ticket costs $15 and a student ticket costs $11<span>
=> sale = 15a +</span><span> 11s
- The auditorium will seat 300 ticket-holders =>
(1) a + s ≤ 300
- The drama club wants to collect at least $3630 from ticket sale =>
(2) 15a + 11 s ≥ 3630
(3) a ≥ 0
(4) s ≥ 0 </span>
Graph
- Draw the s-axis, and highlight the positive part (s ≥ 0)
- Draw the a- axis, and highlight the positive part (a ≥ 0)
- Draw the line <span> a + s = 300 ; use the points (0,300) and (300, 0) which are the extremes of the line
- Shadow the region below the line (a + s ≤ 300)</span>
- Draw the line 15 a + 11 s = 3630; use the points (0, 242) and (330,0) which are the extrems of the line
- Shadow the region above the line (15a + 11s ≥ 3630)
The solution is the region that you shadowed twice: a triangle, located between the two inclined lines, at the left of the shadowed region.
b) List three combination of tickets that satisfy the inequalities
Choose some points that are in the solution region. For example:
1) s = 10, a = 250
2) s = 40, a = 240
3) s = 0, a = 300
I believe the answer would be C)
