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3 years ago

Find the sum of the given polynomials.

Mathematics

2 answers:

slega [8]3 years ago

6 0

Rearrange the equation for like terms:

7b - 4b <span>- 3b </span>+ 3 + 5 + 2

= 10

hammer [34]3 years ago

5 0

Answer:

Step-by-step explanation:

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Find the simple interest on $1500 for 5 years at 3.5%

antoniya [11.8K]

Answer:

$1781.53

Step-by-step explanation:

Simple Interest Rate Formula: A = P(1 + r)ⁿ

Step 1: Define variables

Principle amount <em>P </em>= 1500

Rate <em>r</em> = 0.035

Years <em>n</em> = 5

Step 2: Substitute and Evaluate for A

A = 1500(1 + 0.035)⁵

A = 1500(1.035)⁵

A = 1500(1.18769)

A = 1781.53

3 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!

Mandarinka [93]

Answer:

C) If you live in a mansion, then you do not have a small lawn to mow.

Step-by-step explanation:

<u> Statement is </u>

If you have a small lawn to mow, then you do not live in a mansion.
"If p then q"

<u>Equivalent statements to the given one: </u>

1. Not p or q
2. q or not p
3. If not q then not p

<u>Options to identify equivalent statement </u>

A) If you have a small lawn to mow, then you live in a mansion.

False

B) If you do not have a small lawn to mow, then you live in a mansion.

False

C) If you live in a mansion, then you do not have a small lawn to mow.

True as per rule 3

D) If you do not live in a mansion, then you have a small <u>yard </u>to mow.

False

Correct answer is option C

8 0

3 years ago

Q1 A ball is thrown upwards with some initial speed. It goes up to a height of 19.6m and then returns. Find (a) The initial spee

lubasha [3.4K]

Answer:

(a) 19.6 ms⁻¹

(b) 2 s

(d) 4 s

Step-by-step explanation:

<u>Constant Acceleration Equations (SUVAT)</u>

$\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}$

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Acceleration due to gravity = 9.8 ms⁻².

When the ball reaches its maximum height, its velocity will momentarily be zero.

<u>Given values</u> (taking up as positive):

$s=19.6 \quad v=0 \quad a=-9.8$

$\begin{aligned}\textsf{Using} \quad v^2&=u^2+2as\\\\\textsf{Substitute the given values:}\\0^2&=u^2+2(-9.8)(19.6)\\0&=u^2-384.16\\u^2&=384.16\\u&=\sqrt{384.16}\\\implies u&=19.6\; \sf ms^{-1}\end{aligned}$

Therefore, the initial speed is 19.6 ms⁻¹.

Using the same values as for part (a):

$\begin{aligned}\textsf{Using} \quad s&=vt-\dfrac{1}{2}at^2\\\\\textsf{Substitute the given values:}\\19.6&=0(t)-\dfrac{1}{2}(-9.8)t^2\\19.6&=4.9t^2\\t^2&=\dfrac{19.6}{4.9}\\t^2&=4\\t&=\sqrt{4}\\\implies t&=2\; \sf s\end{aligned}$

Therefore, the time taken to reach the highest point is 2 seconds.

As the ball reaches its maximum height at 2 seconds, one second before this time is 1 s.

<u>Given values</u> (taking up as positive):

$u=19.6 \quad a=-9.8 \quad t=1$

$\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=19.6+(-9.8)(1)\\v&=19.6-9.8\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}$

The velocity of the ball one second before it reaches its maximum height is the <u>same</u> as the velocity one second after.

<u>Proof</u>

When the ball reaches its maximum height, its velocity is zero.

Therefore, the values for the downwards journey (from when it reaches its maximum height):

$u=0 \quad a=9.8 \quad t=1$

(acceleration is now positive as we are taking ↓ as positive).

$\begin{aligned}\textsf{Using} \quad v&=u+at\\\\\textsf{Substitute the given values:}\\v&=0+9.8(1)\\\implies v&=9.8\; \sf ms^{-1}\end{aligned}$

Therefore, the velocity of the ball one second before <u>and</u> one second after it reaches the maximum height is 9.8 ms⁻¹.

From part (a) we know that the time taken to reach the highest point is 2 seconds. Therefore, the time taken by the ball to travel from the highest point to its original position will also be 2 seconds.

Therefore, the total time taken by the ball to return to its original position after it is thrown upwards is 4 seconds.

4 0

1 year ago

If f(4) = 246.4 when r = 0.04 for the function f(t)- Pelt, then what is the

evablogger [386]

Answer:

The answer is to this is D. 210

7 0

3 years ago

Pls help me<br> I need help guys,and I’m going to give the branliest

skad [1K]

C dude now let me get that Brainly