Dividing both sides by two,
OK, part 1.
When
then
Part 2.
When
then
<h3>
Answer: sometimes true</h3>
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Explanation:
The plane P can be thought of a perfectly flat ground. Now imagine a flag pole which represents line GH. If AB is drawn in chalk on the pavement, and this line AB intersects the base of the flagpole, then we've made AB and GH intersect. However, this example shows that GH is <u>not</u> on the plane P.
Is it possible to have GH be in the the plane? Yes. We could easily draw another chalk line on the ground to have it intersect AB somewhere. But as the previous paragraph says, it's also possible that GH is not in the plane.
Therefore, the statement is sometimes true
Answer:
The answer is C
Sn=3(1-1/2^n)
Step-by-step explanation:
Answer and Step-by-step explanation: With the constant velocity motion formula, we can determine constant velocity of the object in motion whose data we collected:
x = x₀ + vt
Velocity can be calculated as:
v = 3 m/s
The beginning of the data collect, object is 40m away, then x₀ = 40.
So, equation modeling the object's path is x = 40 + 3t.
