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Elodia [21]
4 years ago
9

A gift box’s rectangular base has a perimeter of 92 centimeters. The length of the base is one more than twice the base’s width.

Find the width (in centimeters) of this rectangular base.
Mathematics
1 answer:
kozerog [31]4 years ago
3 0
Assume that the length of the rectangle is "l" and that the width is "w".

We are given that: 
(1) The length is one more than twice the base. This means that:
l = 2w + 1 .......> equation I
(2) The perimeter is 92 cm. This means that:
92 = 2(l+w) ...........> equation II

Substitute with equation I in equation II to get the width as follows:
92 = 2(l+w)
92 = 2(2w+1+w)
92/2 = 3w + 1
46 = 3w + 1
3w = 46-1 = 45
w = 45/3
w = 15

Substitute with w in equation I to get the length as follows:
l = 2w + 1 
l = 2(15) + 1
l = 30 + 1 = 31

Based on the above calculations:
length of base = 31 cm
width of base = 15 cm
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Use the given inverse to solve the system of equations. left brace Start 3 By 3 Matrix 1st Row 1st Column x minus y plus z 2nd C
natka813 [3]

The interpretation of the given question is as follows:

Use the given inverse to solve the system of equations

x- y - z = -6  \\ \\ 2y + z = -6 \\ \\  3x -8 y = - \dfrac{1}{2}

The inverse of  \left[\begin{array}{ccc}1&-1&1\\0&2&1\\3&-8&0\end{array}\right]   is \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right]

x =

y =

z =

Answer:

x = - 1.5

y = - 0.5

z =  - 5

Step-by-step explanation:

Using the correlation  of inverse of matrix AX = B to solve the question above;

AX = B

⇒ A⁻¹(AX)  = A⁻¹ B

X =  A⁻¹ B

So ;

X         =        A⁻¹                             B

\left[\begin{array}{c}x\\y\\z\end{array}\right] =     \left[\begin{array}{ccc}-8&8&3\\-3&3&1\\6&-5&-2\end{array}\right] =   \left[\begin{array}{ccc}-6\\ -6\\- \dfrac{1}{2}\end{array}\right]

   

 \left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(-8*-6)+(8*-6)+(3*-\dfrac{1}{2})\\(-3*-6)+(3*-6)+(1*-\dfrac{1}{2})\\(6*-6)+(5*-6)+(-2* - \dfrac{1}{2})\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(48)+(-48)+(\dfrac{-3}{2})\\(18)+(-18)+(\dfrac{-1}{2})\\(-36)+(30)+(1)\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}(\dfrac{-3}{2})\\(\dfrac{-1}{2})\\(-5)\end{array}\right]

\left[\begin{array}{c}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}-1.5\\-0.5\\ -5\end{array}\right]

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Solve the inequality for x. Show each step of the solution.10x > 2(8x – 3) – 18
Luden [163]

Answer: x<4

Given the inequality:

10x>2(8x-3)-18

We want to solve the inequality for x.

First, distribute the bracket on the right side of the inequality.

\begin{gathered} 10x>2(8x)-2(3)-18 \\ 10x>16x-6-18 \\ 10x>16x-24 \end{gathered}

Next, subtract 10x from both sides of the inequality.

\begin{gathered} 10x-10x>16x-10x-24 \\ 0>6x-24 \end{gathered}

Add 24 to both sides of the inequality.

\begin{gathered} 0+24>6x-24+24 \\ 24>6x \end{gathered}

Divide both sides of the inequality by 6.

\begin{gathered} \frac{24}{6}>\frac{6x}{6} \\ 4>x \\ \implies x

The solution to the inequality is x<4.

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3x + 4 = 7x - 9
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So the value of x is 3.25.

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