Assume that the length of the rectangle is "l" and that the width is "w".
We are given that: (1) The length is one more than twice the base. This means that: l = 2w + 1 .......> equation I (2) The perimeter is 92 cm. This means that: 92 = 2(l+w) ...........> equation II
Substitute with equation I in equation II to get the width as follows: 92 = 2(l+w) 92 = 2(2w+1+w) 92/2 = 3w + 1 46 = 3w + 1 3w = 46-1 = 45 w = 45/3 w = 15
Substitute with w in equation I to get the length as follows: l = 2w + 1 l = 2(15) + 1 l = 30 + 1 = 31
Based on the above calculations: length of base = 31 cm width of base = 15 cm
