Answer:
i think its points + what u said
Step-by-step explanation:
mooo
To answer this question, first
let ∫ √(t³+1) dt = g(t) + C
<span>Then g'(t) = √(t³+1) </span>
<span>F(x) = ∫₀ˣ √(t³+1) dt = g(t) |₀ˣ = g(x) - g(0) </span>
<span>Now g(x) is some function of x, while g(0) is a constant </span>
<span>F(x) = g(x) - g(0) </span>
<span>Differentiate both sides: </span>
<span>F'(x) = g'(x) - 0 = √(x³+1) </span>
<span>So you are correct, in this case, we simply replace t with x (this is not always the case) </span>
<span>F'(2) = √(2³+1) = √9 = 3 </span>
<span>You MUST remember that when dealing with square roots, we have: </span>
<span>x² = 4 -----> x = -2 or 2 </span>
<span>x = √4 ----> x = 2 </span>
<span>That's why in the quadratic formula: x = (-b ± √(b²-4ac)) / (2a), we use a ± sign in front of square root, otherwise, if we could willy-nilly assign positive and negatives value to √(b²-4ac), then we would have no need for the ± sign. </span>
<span>Also, when solving x² = 4, we usually have intermediate step </span>
<span>x = ± √4, where +√4 (or simply √4) = 2, and -√4 = 2
</span>
Answer:
8.85
Step-by-step explanation:
2.3+3.75+1.4+1.4
Answer: Lower = 1 Median = 2 Upper = 4
Upper ≠ 1 so statement is false
<u>Step-by-step explanation:</u>
The Lower quartile (Q1) is the left side of the box.<em> I estimate it to be 1.</em>
The Median (Q2) is the line dividing the box.<em> I estimate it to be 2.</em>
The Upper quartile (Q3) is the right side of the box.<em> I estimate it to be 4.</em>
<em />
The upper quartile is the 75th percentile. It is not 1 so the statement is false.
