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lisov135 [29]
3 years ago
5

Hi everyone who here is a blink or army

Mathematics
2 answers:
MissTica3 years ago
5 0

Answer:

I am here........

nice to meet you

anygoal [31]3 years ago
4 0

Answer:

Blink

just got the merch now

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A ferris wheel has a radius of 50 feet, how many feet would it take to go around the entire ferris wheel (the circumference)?
motikmotik

Answer: 314.16 or 100 pie

Step-by-step explanation:

2(50)pie

3 0
3 years ago
Read 2 more answers
1/2 divided by 3 (im doing a quiz and im stuck lol(
Irina18 [472]

Answer:

Isn't it 1/6

Step-by-step explanation:

1      .                  1

_     _   3    =      _

2     .                   6

4 0
3 years ago
Read 2 more answers
Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. N an 1 4 2 −12 3 36 t
Rzqust [24]

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is                    \sum_{n=4}^{15} 5(-2)^{n-1}$$  

<h3>What is sequence ?</h3>

Sequence is collection of  numbers with some pattern .

Given sequence

a_{1}=5\\\\a_{2}=-10\\\\\\a_{3}=20

We can see that

\frac{a_1}{a_2}=\frac{-10}{5}=-2\\

and

\frac{a_2}{a_3}=\frac{20}{-10}=-2\\

Hence we can say that given sequence is Geometric progression whose first term is 5 and common ratio is -2

Now n^{th}  term of this Geometric progression can be written as

T_{n}= 5\times(-2)^{n-1}

So summation of 15 terms can be written as

\sum_{n=4}^{15} T_{n}\\\\$\\$\sum_{n=4}^{15} 5(-2)^{n-1}$$

By applying basic property of Geometric progression we can say that sum of 15 terms of a sequence whose first three terms are 5, -10 and 2 is                    \sum_{n=4}^{15} 5(-2)^{n-1}$$  

To learn more about Geometric progression visit : brainly.com/question/14320920

8 0
3 years ago
Point C ∈ AB , AB = 30m. Point C is 1.5 times farther from point A than from point B. Find AC and CB.
Shtirlitz [24]

let's say that C is "x" units farther from B, that means that CB = x, and therefore AC = 1.5x.


\bf \underset{\leftarrow ~~30~~\to}{\boxed{A}\stackrel{1.5x}{\rule[0.35em]{18em}{0.25pt}}C\stackrel{x}{\rule[0.35em]{10em}{0.25pt}}\boxed{B}}&#10;\\\\\\&#10;AB=AC+CB\implies \stackrel{AB}{30}=\stackrel{AC}{1.5x}+\stackrel{CB}{x}\implies 30=2.5x&#10;\\\\\\&#10;\cfrac{30}{2.5}=x\implies 12=x&#10;\\\\[-0.35em]&#10;~\dotfill\\\\&#10;AC=1.5(12)\implies AC=18~\hspace{8em} CB=x\implies CB=12

8 0
3 years ago
the length of rectangle exceeds its breadth by 4 cm if the length and breadth is increased by 3 cm the area of the new rectangle
gizmo_the_mogwai [7]

Answer:

The length and breadth are 14 cm and 10 cm

3 0
3 years ago
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