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Y_Kistochka [10]
3 years ago
10

Nathan works for a company that provides props to theater groups. He needs to make a stop sign that is the same size as in real

life. On a standard stop sign, the red octagon has a distance of 750 millimeters from the midpoint of one of its sides to the midpoint of the opposite side. To the nearest millimeter, what is the perimeter of the red octagon on the stop sign that Nathan must make?
Mathematics
1 answer:
Nat2105 [25]3 years ago
4 0

Answer:

I believe the answer is 6000 millimeters. I am sorry if this answer is wrong. But I think it may be 6000 or close to it. Again I am super sorry if it is wrong. Have a nice day!!

Step-by-step explanation:

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Suppose the true proportion of voters in the county who support a restaurant tax is 0.54. Consider the sampling distribution for
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Answer:

The correct answer is:

(a) 0.54

(b) 0.0385

Step-by-step explanation:

Given:

Restaurant tax,

p = 0.54

Sample size,

n = 168

Now,

(a)

The mean will be:

⇒ μ \hat{p}= p

         =0.54

(b)

The standard error will be:

\sigma \hat{p} = \sqrt{[\frac{p(1-p)}{n} ]}

    = \sqrt{[\frac{(0.54\times 0.46)}{168} ]}

    = \sqrt{[\frac{(0.2484)}{168} ]}

    = 0.0385

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Use the quadratic formula to find solutions to the following:
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A person on a moving sidewalk travels 6 feet in 3 seconds. The moving sidewalk has a length of 80 feet. How long will it take to
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Step-by-step explanation:

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A set of 12 windup toys costs $9. What is the cost per windup toy?
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Read 2 more answers
100 POINTSSS! ASAP ANSWEERR PLS
Margarita [4]

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = \frac{FV-SV}{SV}*100        (FV = final value, SV = starting value)

Percentage increase = \frac{1.4214 - 0.7107}{0.7107}*100

Percentage increase = \frac{0.7107}{0.7107}*100

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = \frac{10,201-10,100}{10,100}*100

                                                             = \frac{101}{10,100}*100

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = \frac{10,303.01-10,201}{10,201} *100

                                                              = 1%

PC of product B from 3rd to 4th year =\frac{10,406.04-10,303.01}{10,303.01}*100

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

6 0
3 years ago
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