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Nastasia [14]
4 years ago
12

Which ipv6 prefix will the typical enterprise network receive from the service provider?

Computers and Technology
1 answer:
Marizza181 [45]4 years ago
5 0

Answer: /64

The typical enterprise network receive the ipv6 prefix of /64 from the service provider. This means that the address has a subnet prefix that always contains 64 bits, which includes 48 bits for the site prefix, in addition to 16 bits for the subnet ID.

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Print numbers 0, 1, 2, ..., userNum as shown, with each number indented by that number of spaces. For each printed line, print t
geniusboy [140]

Answer:

Please find the answer below

Explanation:

// Online C compiler to run C program online

#include <stdio.h>

int main() {

   // Write C code here

   //printf("Hello world");

   int userNum;

   int i;

   int j;

   

   scanf("%d", &userNum);

   /* Your solution goes here */

   for(i = 0; i<=userNum; i++){

       for(j = 0; j <= i; j++){

           printf(" ");

       }

       printf("%d\n", i);

   }

   return 0;

}

8 0
2 years ago
Write a date transformer program using an if/elif/else statement to transform a numeric date in month/day format to an expanded
boyakko [2]

I wrote it in Python because it was quick so i hope this is helpful

Answer:

date = input('Enter Date: ')

split_date = date.split('/')

month = split_date[0]

day = split_date[1]

if month == '1':

   english_month = 'January'

   spanish_month = 'Enero'

elif month == '2':

   english_month = 'February'

   spanish_month = 'Febrero'

elif month == '3':

   english_month = 'March'

   spanish_month = 'Marzo'

elif month == '4':

   english_month = 'April'

   spanish_month = 'Abril'

elif month == '5':

   english_month = 'May'

   spanish_month = 'Mayo'

elif month == '6':

   english_month = 'June'

   spanish_month = 'Junio'

elif month == '7':

   english_month = 'July'

   spanish_month = 'Julio'

elif month == '8':

   english_month = 'August'

   spanish_month = 'Agosto'

elif month == '9':

   english_month = 'September'

   spanish_month = 'Septiembre'

elif month == '10':

   english_month = 'October'

   spanish_month = 'Octubre'

elif month == '11':

   english_month = 'November'

   spanish_month = 'Noviembre'

elif month == '12':

   english_month = 'December'

   spanish_month = 'Diciembre'

US_English = f'{english_month} {day}'

International_Spanish = f'{day} {spanish_month}'

print(f'US English Form: {US_English}')

print(f'International Spanish Form: {International_Spanish}')

Input:

3/5

Output:

US English Form: March 5

International Spanish Form: 5 Marzo

Explanation:

You start by taking input from the user then splitting that at the '/' so that we have the date and the month in separate variables. Then we have an if statement checking to see what month is given and when the month is detected it sets a Spanish variable and an English variable then prints it to the screen.

Hope this helps.

7 0
3 years ago
4 brainly
Allushta [10]
Web designers like create websites for businesses
6 0
2 years ago
Write a method that takes a RegularPolygon as a parameter, sets its number of sides to a random integer between 10 and 20 inclus
Sergio [31]

Answer:

import java.lang.Object

import java.lang.Math

public class RegularPolygon  extends java.lang.Object{

  public void randomize(RegularPolygon c){

       int min = 10, max1 = 20;

       double  min1 = 5, max1 = 12;

       double range = (max - min) + 1;

       double range1 = (max1 -min1) + 1

       int side = (Math.random() * range) + min;

       double len = (Math.random() * range1) + min1;

       c.setNumSides(side);

       c.setSideLength( len);

 }

 public static void main(String[] args) {

    RegularPolygon r = new RegularPloygon();

    randomize(r);

 }

}

Explanation:

The randomize method accepts a regular polygon class as its only parameter and assigns a random number of sides and the length of these sides with the 'Math.random' function.

5 0
3 years ago
The term that refers to the standard computer language for creating web pages is called:
Leni [432]

CSS or HTML5

fdjsafhjdshfjdkslahfkdsajf

8 0
3 years ago
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