Answer:
sending rude text messages
Explanation:
There is a lot of ways that you can use the bit locker encryption. Some are when you are authenticating your computer using a TPM. Or when you are authenticating your account using a USB Flash drive, and most on the phones authentication through text messages and all.
The answer is Multitasking. NOS (Network Operating System) has the ability to execute more than one program at a time. It allows different programs to operate on the CPU, effectively giving each program a virtual copy of the CPU while preventing the program from directly manipulating the hardware. The NOS switches the CPU time from one task to another in order to create the idea that several tasks are being executed at the same time, but in reality, only one program is being executed.
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
Answer:
1 no.
ram
2
harmful software to the computer
3
local area network
4
bit
5
ram
6
morris malware
7
hard disk drive
8
read only memory9
gigabyte
hope this will help u
