Answer:
6.4 kilometer
==============================
Step-by-step explanation:
See the attached figure.
Let Julian starts from point O (0,0)
Julian jogs 2 kilometers east ⇒ arrived to point A (2,0)
4 kilometers north ⇒ arrived to point B (2,4)
and then 7 kilometers west ⇒ arrived to point C (-5,4)
How far is Julian from his starting position?
So, it is required to find the distance OC
From the graph OC =
So, the distance from his starting position ≈ 6.4 km (to the nearest tenth of a kilometer)
Answer:
x=-1, 3
2 solutions, strategies=quadratic formula
Step-by-step explanation:
1. square the whole equation
(√2x+3)²=(x)²
2x+3=x²
since it becomes a quadratic equation, take all terms on one side = to 0
x²-2x-3=0
Use the quadratic formula, because the equation cannot be factored.
x=(-b±√b²-4ac)/2a
x=(-(-2)±√4-4×1×-3)/2×1
x=(2±√4+12)/2
x=(2±√16)/2
x=(2±4)/2
x=1±2
x=1+2, 1-2
∴x=-1, 3
Answer:
x = -1, y =7
Step-by-step explanation:
3x+y =4
2x+y=5
Multiply the second equation by -1 and add to the first
3x+y =4
-2x-y=-5
-----------------
x = -1
Now find y
3x+y = 4
3(-1) +y = 4
-3+y = 4
Add 3 to each side
-3+3 +y = 4+3
y =7
Answer:
Tina's house located at point (5,4) is in Quadrant |.
Step-by-step explanation:
If both numbers in the parenthesis are positive, it's put in Quadrant |.
(You can also look up a graph quadrant divider and it will show you)
Answer:yes
Step-by-step explanation: