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dem82 [27]
3 years ago
8

David is deciding between two parking garages. Garage A charges an initial fee of $7 to park plus $3 per hour. Garage B charges

an initial fee of $4 to park plus $4 per hour. Let A represent the amount Garage A would charge if David parks for t hours, and let B represent the amount Garage B would charge if David parks for hours . Write an equation for each situation , in terms of t, and determine which garage would be cheaper if David needs to park for 2 hours .

Mathematics
2 answers:
DedPeter [7]3 years ago
8 0

Answer:

A = 3t + 7, B = 4t + 4, B is cheaper

Step-by-step explanation:

A = 3(2) + 7 = 6 + 7 = 13

B = 4(2) + 4 = 8 + 4 = 12

Nezavi [6.7K]3 years ago
5 0

Answer:

Step-by-step explanation:

Garage A = 7+3t

Garage B = 4+4t

Garage A = 7+6

Garage B = 4+8

B = Cheaper

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Ted is making a bread recipe that uses three 1/4 cups of flour and a muffin recipe that uses 2 3/4 cups of flour eggs. How much
wlad13 [49]

Amount of flour used in bread recipe = 3 \frac{1}{4} cups

Amount of flour used in muffin recipe = 2 \frac{3}{4} cups

We have to determine how much more flour is in the recipe.

Since, more amount of flour is used in bread recipe than in muffin recipe.

Total amount of more flour = 3 \frac{1}{4} - 2 \frac{3}{4}

= \frac{13}{4} - \frac{11}{4}

= \frac{2}{4}

= \frac{1}{2}

Therefore, \frac{1}{2} more cup of flour is used in bread recipe than in muffin recipe.

Now, we will determine the total amount of flour used in both recipe.

Total amount of flour used in bread and muffin recipe

= 3 \frac{1}{4} + 2 \frac{3}{4}

= \frac{13}{4} + \frac{11}{4}

=\frac{24}{4}

= 6 cups

Therefore, total 6 cups of flour are used in both the recipes.

3 0
3 years ago
How to show my work for2+[4+(5x6)]
Setler [38]

Step-by-step explanation:

2+[4+(5*6)]

2+[4+30]

2+34

36

7 0
2 years ago
Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call
Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n-values of normal variable:

Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is M = n\mu and the standard deviation is s = \sigma\sqrt{n}

Calls to a customer service center last on average 2.8 minutes.

This means that \mu = 2.8

75 calls each day.

This means that n = 75

What is the expected total amount of time in minutes the operator will spend on the calls each day

This is M, so:

M = n\mu = 75*2.8 = 210

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

6 0
3 years ago
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