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3 years ago

What is the positive solution to 4x2 + 2x= 42? NEED HELP

Mathematics

1 answer:

VikaD [51]3 years ago

7 0

Answer:

Step-by-step explanation:

first multiply 4 X 2= 8

8+2x=42

Now you are going to pass 8 to the other side by adding -

2x=42-8

2x=34

Now you are going to divide 34 between 2 to eliminate the 2 multiplying in the other side. 34 between 2= 17

X=17

Hope this helps :)

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9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat

Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 2000, p = 1-0.995 = 0.005$

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

$P(X < 5) + P(X \geq 5) = 1$

We want $P(X \geq 5)$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044$

$P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445$

$P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235$

$P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480$

$P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765$

$P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290$

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710$

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0

3 years ago

Ben is making manipulative to sell..He wants to make at least $450.00 ..Each manipulative costs $18 to make.He is selling them f

prohojiy [21]

The least Ben can sell is 37 manipulative to reach his goal.

7 0

3 years ago

NO LINK SPAM OR REPORT: Tell whether x and y show direct variation. Explain your reasoning. If so, find k.

sergeinik [125]

Answer:

2. yes; the equation can be written as y = kx; k = 1

Step-by-step explanation:

x-y = 0

That means x and y have to be the same value.

If you multiply a number by 1, you get the same thing.

If you multiply x by one, you get y (the same value).

Hope this helps!

3 0

2 years ago

2(3x + 5) = 9x + 9 - 3x + 1

ELEN [110]

2(3x+5)=9x+9-3x+1
(2)(3x)+(2)(5)=9x+9-3x+1
6x+10=9x+9-3x+1
6x+10=(9x-3x)+(9+1)
6x+10=6x+10
6x-6x+10=6x-6x+10
10=10
10-10=10-10
0=0
All real numbers are solutions.

3 0

3 years ago

What can go into 81/16??

nordsb [41]

The bets answer that could go into 81 and 16 would be 1

5 0

3 years ago

Read 2 more answers