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2 years ago

I need to know what the LCM for 3 and 8. I am confused since like wouldn't that be nothing :((

Mathematics

2 answers:

VashaNatasha [74]2 years ago

4 0

Answer:

24 is the answer.

Step-by-step explanation:

The LCM of two non-zero integers, x(3) and y(8), is the smallest positive integer m(24) that is divisible by both x(3) and y(8) without any remainder.

Ksju [112]2 years ago

4 0

Answer:

24 is the answer

Step-by-step explanation:

I can't upload the photo sorry

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What is the value of this expression? (37)0 0 37 1 307

Anni [7]

37^0 = 1

Any number to the 0 exponent is equal 1, except 0

Answer

5 0

3 years ago

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How many different 4-question geometry quizzes can a teacher make if there are 7 different problems to test on?.

stich3 [128]

Answer:

35 quizzes

Step-by-step explanation:

We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.

We do this by using the formula $\displaystyle nCr=\frac{n!}{r!(n-r)!}$ which describes the number of ways we can choose $r$ objects given $n$ possible choices. So, if $n=7$ and $r=4$ , then:

$_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35$

Hence, the teacher can make 35 different geometry quizzes.

3 0

2 years ago

PLEASE PLEASE HELP!!!!!

kodGreya [7K]

We need 6.5% to a decimal so..
6.5% /100 = 0.065

$21.30 X 0.065 = 1.3845 tax on the shirt

So.. we add the price of the shirt, and the amount of tax on the shirt
$21.30 + 1.3845 = $22.6845

Answer = $22.68

3 0

2 years ago

PLEASE PLEASE PLEASE HELP FAST!!!!!!!!!! WILL REPORT ANY TROLLS

worty [1.4K]

Answer:

i think its 1.5 im not sure tho 1.5 sounds the best

Step-by-step explanation:

6 0

2 years ago

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An assembly consists of two mechanical components. Suppose that the probabilities that the first and second components meet spec

harkovskaia [24]

Answer:

P(X = 0) = 0.0208, P(X = 1) = 0.2484, P(X = 2) = 0.7308

Step-by-step explanation:

Let's define the following events

A: the first component meet specification

B: the second component meet specification

P(A) = 0.87

P(B) = 0.84

Let X be the random variable that represents the number of components in the assembly that meet specifications. Because there are only two mechanical components in the assembly, X can only take the values 0, 1, 2.

P(X = 0) = P(the first component does not meet specification and the second component does not meet specification) =

$P(A^{c}\cap B^{c}) = P(A^{c})P(B^{c})$ (because of independence)

= (0.13)(0.16) = 0.0208

P(X = 1) = P(only one component meet specification) = P[(the first component meet specification and the second component does not meet specification) or (the first component does not meet specification and the second component meet specification)] =

$P[(A\cap B^{c})\cup (A^{c}\cap B)] = P(A\cap B^{c}) + P(A^{c}\cap B)=$ (because sets are mutually exclusive)

$P(A)P(B^{c}) + P(A^{c})P(B)=$ (because of independence)

= (0.87)(0.16) + (0.13)(0.84) = 0.2484

P(X = 2) = P(both components meet specifications) =

$P(A\cap B) = P(A)P(B)$ (because of independence)

= (0.87)(0.84)

= 0.7308

8 0

3 years ago