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2 years ago

I need to know what the LCM for 3 and 8. I am confused since like wouldn't that be nothing :((

Mathematics

2 answers:

VashaNatasha [74]2 years ago

4 0

Answer:

24 is the answer.

Step-by-step explanation:

The LCM of two non-zero integers, x(3) and y(8), is the smallest positive integer m(24) that is divisible by both x(3) and y(8) without any remainder.

Ksju [112]2 years ago

4 0

Answer:

24 is the answer

Step-by-step explanation:

I can't upload the photo sorry

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Rene is going to the lake to visit some friends if the lake is 60 miles away, and rene is driving a 40 miles per hour the entire

Ostrovityanka [42]

40/60=60/x...forty miles in sixty minutes is equal to 60 miles in 40 minutes.....40x=3600....x=90..90 minutes

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7By%7D%7B2%7D%20%20%3C%20%20-%203" id="TexFormula1" title=" \frac{y}{2} < - 3"

Allisa [31]

Hey!

Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get $y$ on its own.

Original Equation : 
$\frac{y}{2}$ < $-3$

New Equation {Changed by Multiplying 2 on Both Sides} :
$\frac{2y}{2}$ < $2$ ( $-3$ )

And we simplify the equation to get our answer.

Old Equation :
$\frac{2y}{2}$ < $2$ ( $-3$ )

New Equation {Changed by Simplification} :
y < -6

So, the equation $\frac{y}{2}$ < -3 simplified is y < -6.

Hope this helps!

- Lindsey Frazier ♥

8 0

2 years ago

Please help me answer this question?

zalisa [80]

Answer:

2+2

Step-by-step explanation:

2 + 4!

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7 0

1 year ago

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The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an

Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = $\dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}$

Or, w = $\dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}$

Or, w = $\dfrac{-11\pm \sqrt{473}}{2}$

or, w = $\dfrac{-11\pm 21.7}{2}$

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0

3 years ago

Solve the equation N/-2=-15

otez555 [7]

Answer:

Step-by-step explanation:

N/-2=-15

N= -15 times -2

N= 30

4 0

2 years ago

Read 2 more answers