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Artyom0805 [142]

3 years ago

9

You are choosing a book from your friend’s book collection. You can choose 1 of 6 science fiction books, 1 of 2 mystery books, o

r 1 of 3 biographies. How many ways can you choose a book?
Question 2 options:

A)

11

B)

24

C)

30

D)

36

2 answers:

olga_2 [115]3 years ago

8 0

I believe the correct answer would be A) 11.

I hope this helped you! c:

Novosadov [1.4K]3 years ago

4 0

Answer: A.11

Step-by-step explanation:

i did the test

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Write the expression that appears under the radical symbol in the quadratic formula. what is the quality called? what can it be

ira [324]

This expression is called the Discriminant, also shown as Δ.
It is equal to b² - 4ac. This is a very important part of the quadratic formula as it determines whether x will have two values, one repeated value or no real values. Here are a few examples.

a) x² - 2x - 1. a is equal to 1 since 1x² = x². b = -2, c = -1
The discriminant will be (-2)² - 4×1×-1 = 4 + 4 = 8.
Since Δ > 0, there are two x values. Graphed, the parabola sinks below the x axis.

b) x². a = 1, b = 0 (0x = 0), c = 0
The discriminant will be 0² - 4×1×0 = 0 - 0 = 0.
Since Δ = 0, there is only one x value. Graphed, the parabola touches the x axis at only one point.

c) x² + 1. a = 1, c = 1.
The discriminant will be 0² - 4×1×1 = 0 - 4 = -4
Since Δ < 0, there are no real x values. Graphed, the parabola floats above the x axis.

Hope this helps!

8 0

3 years ago

Find the distance between the point (2, 3) and the line 4x + 3y = 10 (round your answer to the nearest tenth).

Monica [59]

Explanation

Let's first graph the elements:

Using the distance formula we get:

$d=\frac{|4(2)+3(3)-10|}{\sqrt{4^2+3^2}}$ $d=\frac{|7|}{\sqrt{25}}=\frac{7}{5}=1.4$

4 0

1 year ago

Please help me with these. These are so hard.<br><br>

LuckyWell [14K]

$\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}$

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0

4 years ago

Hi im Elizabeth and im new what do i do

Gwar [14]

Answer:

You ask and answer questions to get help and help others.

3 0

3 years ago

Read 2 more answers

What is the answer 2y 5x=6

denis-greek [22]

Its simple take out the y and take out the x, you get 25=6!!!!!!!

4 0

4 years ago