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Naily [24]
3 years ago
13

Lisa is 53 3 4 inches tall. Joey is 1 1 2 inches shorter than Lisa and Jane is 1 1 5 inches shorter than Joey. How tall is Jane?

Mathematics
1 answer:
tester [92]3 years ago
3 0

Answer: Jane's height =  51\dfrac{1}{20}\text{ inches}

Step-by-step explanation:

Given: Lisa's height = 53\dfrac34\text{ inches}=\dfrac{4\times53+3}{4}\text{ inches}

=\dfrac{215}{4}\text{ inches}

Joey's height = \dfrac{215}4-1\dfrac12 inches

=\dfrac{215}4-\dfrac32\\\\=\dfrac{215-6}{4}\\\\=\dfrac{209}{4}\text{ inches}

Jane's height = \dfrac{209}{4}-1\dfrac15 inches

=\dfrac{209}{4}-\dfrac{6}{5}\\\\=\dfrac{209\times5-6\times4}{20}\\\\=\dfrac{1045-24}{20}\\\\=\dfrac{1021}{20}\\\\=51\dfrac{1}{20}\text{ inches}

Hence, Jane's height = 51\dfrac{1}{20}\text{ inches}

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