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2 years ago

Lisa is 53 3 4 inches tall. Joey is 1 1 2 inches shorter than Lisa and Jane is 1 1 5 inches shorter than Joey. How tall is Jane?

Mathematics

1 answer:

tester [92]2 years ago

3 0

Answer: Jane's height = $51\dfrac{1}{20}\text{ inches}$

Step-by-step explanation:

Given: Lisa's height = $53\dfrac34\text{ inches}=\dfrac{4\times53+3}{4}\text{ inches}$

$=\dfrac{215}{4}\text{ inches}$

Joey's height = $\dfrac{215}4-1\dfrac12$ inches

$=\dfrac{215}4-\dfrac32\\\\=\dfrac{215-6}{4}\\\\=\dfrac{209}{4}\text{ inches}$

Jane's height = $\dfrac{209}{4}-1\dfrac15$ inches

$=\dfrac{209}{4}-\dfrac{6}{5}\\\\=\dfrac{209\times5-6\times4}{20}\\\\=\dfrac{1045-24}{20}\\\\=\dfrac{1021}{20}\\\\=51\dfrac{1}{20}\text{ inches}$

Hence, Jane's height = $51\dfrac{1}{20}\text{ inches}$

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