Answer:
The equivalent will be:
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D%3D%5Cleft%28%5C%3Ax%5E%7B%5Cfrac%7B2%7D%7B7%7D%7D%5Cright%29%5Cleft%28y%5E%7B-%5Cfrac%7B3%7D%7B5%7D%7D%5Cright%29)
Therefore, option 'a' is true.
Step-by-step explanation:
Given the expression
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D)
Let us solve the expression step by step to get the equivalent
as
![\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E2%7D%3D%5Cleft%28x%5E2%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B7%7D%7D)
∵ ![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
also
![\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%5E3%7D%3D%5Cleft%28y%5E3%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D)
∵
so the expression becomes
∵ 
Thus, the equivalent will be:
Therefore, option 'a' is true.
who knowsAnswer:
Step-by-step explanation: idk
Answer: x and y intercepts are where the line crosses over the x and y axis.
Step-by-step explanation:
We can solve it like:
3x^3+3x^2+x+1= (3x^3+3x^2)+(x+1)=
3x^2(x+1)+(x+1)=
= (x+1)(3x^2+1)
Have a good day
We will need an image but i am happy to change my answer with the correct answer as soon as we have what we need
