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kolezko [41]
3 years ago
11

Mitch is buying candy bars for his friends. He wants to give 2 bars to each friend, and wants to have 10 spare bars. He can affo

rd to buy 36 candy bars. How many friends can he treat?
Mathematics
1 answer:
kondaur [170]3 years ago
3 0

Answer:

Mitch can give 2 candy bars to 13 friends

Step-by-step explanation:

first, since he wants 10 left over, you subtract 36-10 which is 26. Then, since he wants to give each friend 2 candy bars, you divide 26 by 2 which equals 13.

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G. r. a. p. h. 24x-6y=18.
FinnZ [79.3K]
24x−6y=18 Step 1: Add 6y to both sides. 24x−6y+6y=18+6y24x=6y+18

Step 2: Divide both sides by 24.24x24=6y+1824x=14y+34

Answer: x=14y+34
6 0
2 years ago
Standard automobile license plates in a country display 2 digits, followed by 2 letters, followed by 3 digits. How many differen
fomenos

Answer:

There are 1,892,800,000 different standard plates that are possible in this system

Step-by-step explanation:

The plates follow the following format:

D - D - L - L - L - D - D - D

For each digit there are 10 possible outcomes, and for each letter there are 26 possible outcomes.

So, there are

10*10*26*26*28*10*10*10 = 1,892,800,000

different standard plates that are possible in this system

3 0
3 years ago
Sharing objects one at a time until there are none left
Rom4ik [11]
Do you mean like equal groups
4 0
3 years ago
1. & 2. In the diagram below, points A, B, and C are collinear. Answer each of the following questions. The figure shown bel
Lana71 [14]

Answer:

a)  \overline{AB} = 8 in

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. \overline{AB} = 10 in

c)  When the length of AB = 10.2 in. and BC = 3.7 in.  \overline {AC}  = 6.5 in

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. \overline {BC} =  1\frac{1}{2} in

Step-by-step explanation:

a) When the length of AC = 5 in. and CB = 3 in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 5 in. + 3 in. = 8 in.

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 6\frac{1}{2} in.+ 3\frac{1}{2} in. = 10 in.

c) When the length of AB = 10.2 in. and BC = 3.7 in. we have;

The length of \overline {AC} = AB - BC (converse of the segment addition postulate)

Therefore;

\overline {AC} = 10.2 in.+ 3.7 in. = 6.5 in.

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. we have;

The length of \overline {BC} = AB - AC (converse of the segment addition postulate)

Therefore;

\overline {BC} = 4\frac{3}{4} in. -  3\frac{1}{4} in.=  1\frac{1}{2} in.

6 0
2 years ago
What is the quotient of the division below?<br><br> 612 divided by 9 =
lora16 [44]

Answer:

68

Step-by-step explanation:

4 0
2 years ago
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