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butalik [34]
3 years ago
14

Ron's property tax is $615.33 and is due April 5. He does not pay until July 19. The country adds a penalty of 8.4% simple inter

est on unpaid tax. Find the penalty Ron will pay. (assume there are 365 days in a year)
Mathematics
1 answer:
dolphi86 [110]3 years ago
6 0
Number of days that attracted penalty is from April 5 to July 19 which is 105 days.

Thus the amount of simple interest attracted by Ron is given by:

S.I.= \frac{615.33\times8.4\times105}{100\times365} = \frac{542,721.06}{36500} =\$14.87
You might be interested in
Simplify the following radical expressions. 100 points<br> √8/√6<br> √2/10<br> √532<br><br> √3k√8
kenny6666 [7]

Answer:

√8/√6=1.632993

√2/10=0.141421

√3k√8=4.898979k

Step-by-step explanation:

or did u want it in a different form

7 0
3 years ago
For each trip, a taxi company charges a fixed fee of $2.00 plus $0.75 for each 1/2 mile or fraction of 1/2 miles. If, for every
nydimaria [60]

Answer:

E: 2.00 + 0.75 [ 2r]

Step-by-step explanation:

r represents the number of miles. For each 1/2 mile the taxi will charge and extra free of $0.75. Then, for each mile, the taxi will charge $0.75*2. For example:

For a trip of 1 mile the taxi will charge:

$2.00+$0.75*2

For a trip of 2 miles, the taxi will charge:

$2.00+0.75*4

For a trip of 10 miles, the taxi will charge:

$2.00+$0.75*20

Notice that the variable fee (the one that depends on the number of miles) is $0.75 times the double of miles. In each case the number of miles is multiplied by two. Then the correct answer is E: 2.00 + 0.75 [ 2r]

5 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
Jerome burns 4 cal/min walking and 10 cal/min running. He walks between 10 and 20 min each day and runs between 30 and 45 min ea
erik [133]

Answer:

20 minutes should spend on walking and 30 minutes on running.

Step-by-step explanation:

Let x represents the minutes spent on walking and y represents the minutes spent on running,

∵ He burns 4 cal/min walking and 10 cal/min running,

So, the total calories burnt,

Z = 4x + 10y

Which has to be maximised.

Now, he walks between 10 and 20 min each day,

i.e. 10 < x < 20,

Also, he runs between 30 and 45 min each day,

i.e. 30 <  y < 45,

By graphing 10 < x < 20 and 30 <  y < 45,

We obtained the vertices of feasible region,

(10, 45), (20, 45), (10, 30) and (20, 30)

At (10, 45),

Z = 4(10) + 10(45) = 40 + 450 = 490,

At (20, 45),

Z = 4(20) + 10(45) = 80 + 450 = 530,

At (10, 30),

Z = 4(10) + 10(30) = 40 + 300 = 340,

At (20, 30)

Z = 4(20) + 10(30) = 80 + 300 = 380

Hence, maximum calories is 530 when 20 minutes spent on walking and 30 minutes spent on running.

5 0
3 years ago
Evaluate-a-function f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B7%7D" id="TexFormula1" title="\frac{x}{7}" alt="\f
OLga [1]

Step-by-step explanation:

Hey there!

f(x) = 7/x

<em>~ Simply keep the "7" in the place where "x" is there.</em>

f(7) =  \frac{7}{7}

Therefore, X= 1.

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
3 years ago
Read 2 more answers
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