We need to estimate how tall is, on average, one of these object, and then count how many would be in a 5 feet high stack.
For example, on Google you may see that "1.5 cubic foot boxes are the standard box, manufactured by most companies". So, we assume that a standard cardboard box is 1.5 feet tall.
So, if we set the equation
![1.5k = 5 \iff k=\dfrac{5}{1.5}=3.\bar{3}](https://tex.z-dn.net/?f=1.5k%20%3D%205%20%5Ciff%20k%3D%5Cdfrac%7B5%7D%7B1.5%7D%3D3.%5Cbar%7B3%7D)
So, there would be between 3 and 4 cardboard boxes in a 5 feet tall stack.
Similarly, we can see that the average book is 9 inches tall. 9 inches are 0.75
feet, so we have
![0.75k=5 \iff k=6.\bar{6}](https://tex.z-dn.net/?f=0.75k%3D5%20%5Ciff%20k%3D6.%5Cbar%7B6%7D)
So, there would be between 6 and 7 books in a 5 feet tall stack.
The average brick is 75 millimeters tall, which means 0.25 feet tall. Again, we have
![0.25k=5 \iff k=20](https://tex.z-dn.net/?f=0.25k%3D5%20%5Ciff%20k%3D20)
So, there would be 20 bricks in a 5 feet tall stack.
Finally, a coin is about 0.006 feet, which leads to
![0.006k=5 \iff k=833.\bar{3}](https://tex.z-dn.net/?f=0.006k%3D5%20%5Ciff%20k%3D833.%5Cbar%7B3%7D)
So, there would be between 833 and 834 coins in a 5 feet tall stack.