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grin007 [14]
3 years ago
14

Select Expansion or Contraction to correctly describe the type of dilation for each given scale factor.

Mathematics
1 answer:
Tanya [424]3 years ago
5 0

Answer:


Step-by-step explanation:

if you are going in a negative direction or by a decimal you are contracting, so the image would get smaller. If you are going in a positive direction(has to be a whole number as well) you have an expansion.

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Hey can you please help me posted picture of question
Galina-37 [17]
Since the events are dependent, the probability of occurrence of event B will impact the probability of occurrence of event A. So we will be using the formula of conditional probability to find P(A ∩ B).

P(A|B)= \frac{P(A*B)}{P(B)} \\  \\ 
P(A*B)=P(A|B)P(B)

Here P(A*B) indicates P(A ∩ B).

Using the values, we get:

P(A ∩ B) = 0.25 x 0.4 = 0.1

Thus, option A gives the correct answer.
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After the row and column reductions, what is the minimum number of lines needed to cover the zero's?
HACTEHA [7]
C .2 lines should be the answer
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Which one is the farthest<br> from sea level? crab -30, whale 0<br> Seagull 20, or dolphin 5?
Semmy [17]
The seagull is the furthest away from sea level
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3 years ago
Read 2 more answers
A researcher wants to estimate the percentage of all adults that have used the Internet to seek pre-purchase information in the
Lubov Fominskaja [6]

Answer:

The required sample size for the new study is 801.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

25% of all adults had used the Internet for such a purpose

This means that \pi = 0.25

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

What is the required sample size for the new study?

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.25*0.75)}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.25*0.75}

\sqrt{n} = \frac{1.96\sqrt{0.25*0.75}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.25*0.75}}{0.03})^2

n = 800.3

Rounding up:

The required sample size for the new study is 801.

4 0
3 years ago
Find the area of the triangle with the given measurements. Round the solution to the nearest hundredth if necessary.
Rama09 [41]

Check the picture below.

now, we have a triangle with all three sides, thus we can use Heron's Area Formula on the triangle.

\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=10\\ b=26.695\\ c=22\\ s=29.3475 \end{cases} \\\\\\ A=\sqrt{29.3475(29.3475-10)(29.3475-26.695)(29.3475-22)} \\\\\\ A=\sqrt{29.3475(19.3475)(2.6525)(7.3475)}\implies A\approx \sqrt{11066.007} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 105.195~\hfill

4 0
3 years ago
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